When KM is much greater than the [S]:
Please choose the correct answer from the following choices

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BlackTom AI · Accepted Answer

First, let’s restate the scenario and the options to make sure we’re evaluating the same statements. Question: When Km is much greater than the [S], please choose the correct answer from the following choices. Answer options: - The V0 is approximately equal to KM. - The V0 is approximately Vmax. - The V0 is approximately equal to KM/2. - The V0 is approximately proportional to [S]. - The V0 is approximately Vmax/2. Now, we’ll inspect each option in turn to see what the Michaelis–Menten relationship implies in the regime Km >> [S]. Option 1: The V0 is approximately equal to KM. This is not correct. When [S] is much smaller than Km, the denominator Km + [S] is dominated by Km, so V0 ≈ (Vmax [S])/Km, which clearly depends on [S] and is not a constant equal to Km. Option 2: The V0 is approximately Vmax. This would be true if [S] were much larger than Km (saturation), where V0 approaches Vmax. But with Km >> [S], we are far from saturation, so V0 is far below Vmax. Therefore this statement is false in this regime. Option 3: The V0 is approximately equal to KM/2. This would imply a specific, fixed fraction of Km independent of [S], which does not align with the Michaelis–Menten form under Km >> [S], where V0 scales with [S]. Hence this is incorrect. Option 4: The V0 is approximately proportional to [S]. This matches the derived expression V0 ≈ (Vmax/Km) [S] when [S] << Km. Here, V0 grows linearly with substrate concentration with a proportionality constant Vmax/Km, so this statement is consistent with the model in this limit. Option 5: The V0 is approximately Vmax/2. This is a characterization of the half-maximal rate, which occurs when [S] ≈ Km, not when Km >> [S]. Therefore it does not describe the Km >> [S] regime. To summarize, in the limit Km >> [S], the reaction velocity V0 is not near Vmax, not near KM, and not a fixed fraction of KM or Vmax; instead it scales linearly with the substrate concentration [S], with V0 ≈ (Vmax/Km) [S]. This makes Option 4 the correct statement for this situation. All other options mischaracterize the relationship between V0, [S], Km, and Vmax in the Km >> [S] regime.

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When KM is much greater than the [S]: Please choose the correct answer from the following choices

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