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题目
CHEM 1220 SP2025 (18215) Exam 4- Requires Respondus LockDown Browser
多重下拉选择题
For each of the following reactions, will ΔSsys be positive, negative or zero? I. SrCO3(s) → Sr2+(aq) + CO32–(aq) [ Select ] zero positive negative II. CH3NH2(g) + HCl(g) → CH3NH3Cl(s) [ Select ] positive zero negative III. 2 H2O2(g) → O2(g) + 2 H2O(g) [ Select ] negative zero positive 09B
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标准答案
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思路分析
For this question, we need to judge the sign of the entropy change of the system (ΔSsys) for each reaction.
I. SrCO3(s) → Sr2+(aq) + CO3 2–(aq)
- In a solid salt dissolving into aqueous ions, the solid state becomes disperse......Login to view full explanation登录即可查看完整答案
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类似问题
Using the following So values H2O(g), So = 188.83 J·mol-1·K-1 O2(g), So = 205.0 J·mol-1·K-1 CO2(g), So = 213.6 J·mol-1·K-1 CH3OH(g), So = 237.6 J·mol-1·K-1 Calculate ΔSo in J mol-1 K-1 for the following reaction. 2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)
Calculate the value of S° for the reaction shown: 2 NH3(g) N2(g) + 3 H2(g) At 25°C the values of entropy in J K−1 mol−1 are ammonia, 192.77; nitrogen, 191.61; and hydrogen, 130.68.
Propanol (C3H8O) has a boiling point of 97.0 ºC and ΔHvap =42.27 kJ mol-1. Calculate ΔS for the process given below. CH3CH2CH2OH (l) → CH3CH2CH2OH (g)
Using the following So values H2O(g), So = 188.83 J·mol-1·K-1 O2(g), So = 205.0 J·mol-1·K-1 CO2(g), So = 213.6 J·mol-1·K-1 CH3OH(g), So = 237.6 J·mol-1·K-1 Calculate ΔSo in J mol-1 K-1 for the following reaction. 2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)
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为了让更多留学生在备考与学习季更轻松,我们决定将Gold 会员限时免费开放至2025年12月31日!