There are 2
points near a positive point charge Point 1 and Point 2. 1) Find the ratio (E1/E2) of electric field strength?

Question

BlackTom AI · Accepted Answer

We start by recalling the basic relation for the electric field due to a point charge: E = kq / r^2, where r is the distance from the charge." +
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To compare E1 and E2 at two locations Point 1 and Point 2, we use the inverse-square dependence: E1 / E2 = (r2^2) / (r1^2)." +
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From the diagram, Point 2 lies farther from the charge than Point 1. If the distances are such that r2 = 3 r1 (i.e., Point 2 is three times as far away as Point 1), then" +
  "
E1 / E2 = (r2^2) / (r1^2) = (3 r1)^2 / (r1^2) = 9." +
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Interpretation note: the key step is recognizing the r^2 dependence of the field magnitude and substituting the correct distance ratio between the two points. If the actual distance ratio were different, the ratio E1 / E2 would change accordingly, since it scales with the square of the distance ratio." +
  "

Since the problem involves a single positive point charge and two locations at known relative distances, the ratio is determined entirely by how much farther Point 2 is compared to Point 1.

MCD1200 Physics A / MCD4600 Intermediate Physics - Trimester 1 - 2025

There are 2 points near a positive point charge Point 1 and Point 2. 1) Find the ratio (E1/E2) of electric field strength?

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