An object with a 5.0 μC charge is accelerating at 0.0050 m/s2 due to an electric field. If the object has a mass of 2.0´10-3 kg, what is the magnitude of the electric field?

Question

BlackTom AI · Accepted Answer

To find the electric field magnitude, we relate the electric force to the field and to the motion of the charge.
First, recall F = ma and F = qE. Equating these gives qE = ma, so E = ma/q.
Now plug in the given values: m = 2.0 × 10^-3 kg and a = 0.0050 m/s^2, so ma = (2.0 × 10^-3)(0.0050) = 1.0 × 10^-5 N.
Next, q = 5.0 μC = 5.0 × 10^-6 C. Therefore E = (1.0 × 10^-5 N) / (5.0 × 10^-6 C) = 2.0 N/C.
The calculated magnitude is 2.0 N/C, which corresponds to the provided option. If there were other options, this value would be compared against them to determine which is correct, but with the given data, the field magnitude evaluates to 2.0 N/C.

SPHY001 Practice Quiz - Unit 18 | LA058

An object with a 5.0 μC charge is accelerating at 0.0050 m/s2 due to an electric field. If the object has a mass of 2.0´10-3 kg, what is the magnitude of the electric field?

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