How much energy is stored in a spring of constant 60.8 Nm-1 when it is compressed by 0.3 m? Give your answer to two decimal places.

Question

BlackTom AI · Accepted Answer

To determine the energy stored in a compressed spring, recall the formula for elastic potential energy: E = (1/2) k x^2.
First, identify the given values: spring constant k = 60.8 N/m and compression x = 0.3 m. 
Next, square the displacement: x^2 = (0.3 m)^2 = 0.09 m^2. 
Then, multiply by the spring constant and take half: E = (1/2) * 60.8 N/m * 0.09 m^2 = 30.4 * 0.09 J.
Compute the product: 30.4 * 0.09 = 2.736 J. 
Finally, round to two decimal places as requested: E ≈ 2.74 J.
Note: there are no multiple-choice options provided to evaluate; we directly apply the standard formula for elastic potential energy and perform the calculation with the given values. If any step seems unclear, remember that the core ideas are (a) energy depends on both stiffness and displacement, (b) displacement should be squared, and (c) a factor of 1/2 is required for the energy expression.

MUF0121 Physics Unit 1 - Semester 2, 2025 6.10 Energy

How much energy is stored in a spring of constant 60.8 Nm-1 when it is compressed by 0.3 m? Give your answer to two decimal places.

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