True or False: Suppose that A is a 3x3 matrix whose eigenvalues are -3, 5 and 1/2. Then it must be the case that A is an invertible matrix.

Question

BlackTom AI · Accepted Answer

Consider the statement and its implications by analyzing what eigenvalues tell us about invertibility.
Option 1 (True): If a square matrix has an eigenvalue of 0, then the matrix is singular and not invertible; equivalently, a matrix is invertible precisely when none of its eigenvalues are zero. In this case, the eigenvalues are -3, 5, and 1/2, none of which are zero. Therefore, the determinant (which equals the product of the eigenvalues for a square matrix) is (-3) × 5 × (1/2) = -15/2 ≠ 0, which confirms invertibility.
Option 2 (False): If one were to claim the matrix must not be invertible, the reasoning would require a zero eigenvalue or a zero determinant. Since all given eigenvalues are nonzero, this line of reasoning is flawed; there is no evidence here that would force a zero determinant or a noninvertible transformation, so this option is incorrect.
Additional perspective: Invertibility is equivalent to the absence of zero in the spectrum of the matrix. Here, the spectrum is { -3, 5, 1/2 }, which clearly excludes 0, reinforcing the conclusion that A is invertible.
A potential misconception to watch for: believing that a matrix with nonzero eigenvalues might still fail to be invertible due to some other property. However, for square matrices over the reals or complexes, nonzero eigenvalues guarantee a nonzero determinant and thus invertibility, so that idea does not apply here.
In summary, the presence of only nonzero eigenvalues directly contradicts any claim of noninvertibility and supports the invertibility of A.

True or False: Suppose that A is a 3x3 matrix whose eigenvalues are -3, 5 and 1/2. Then it must be the case that A is an invertible matrix.

查看解析

登录即可查看完整答案

类似问题

True or False: If 'L' is an eigenvalue for some square matrix, A, then 'L' must also be an eigenvalue for the square matrix A-1.

True or False: If 'L' is an eigenvalue for some square matrix, A, then 'L' must also be an eigenvalue for the square matrix AT.

Question20 Consider the matrix [math]. What are the eigenvalues of this matrix?Select one alternative: 1 and 5 1 and 6 0 and 5 0 and 6 ResetMaximum marks: 1 Flag question undefined

Let the matrix 𝑋 be 𝑋 = [ − 9 4 − 7 𝑘 ] . For 𝑋 to have 0 as an eigenvalue, what must 𝑘 be?

Let the matrix X be X=[−9 4 −7 k]. For X to have 0 as an eigenvalue, what must k be?

Let the matrix X be X=[4 −1 1 k]. For X to have 0 as an eigenvalue, what must k be?

Let the matrix \(X\) be \[X = \left [\begin{matrix}8 & -2\\-6 & k\end{matrix}\right ].\] For \(X\) to have \(0\) as an eigenvalue, what must \(k\) be?

Suppose A is an n×n symmetric positive definite matrix and A=B2. Given that the eigenvalues of A are 18.5 and 9.5, find the eigenvalues of B.

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单