Calculate the following dilutions:

A. A 1:2 grape juice solution in a total volume of 5 ml.

B. A 1:5 dilution of grape juice in a total volume of 5 ml.

Dilutions Amount of Water (ml) Amount of Juice (ml)
1:2
1:5

Question

Calculate the following dilutions:

A. A 1:2 grape juice solution in a total volume of 5 ml.

B. A 1:5 dilution of grape juice in a total volume of 5 ml.

Dilutions	Amount of Water (ml)	Amount of Juice (ml)
         1:2		
        1:5

BlackTom AI · Accepted Answer

Restating the problem in my own words: you are asked to calculate two dilutions in a total volume of 5 ml each. A is a 1:2 dilution of grape juice, and B is a 1:5 dilution, with a provided table showing amounts of water and juice. The answer options give specific amounts of water and juice for A and B, and you must evaluate each option.

First, let's consider how to interpret a 1:2 or 1:5 dilution. A common convention for dilutions is to interpret a ratio as juice (solvent or solute of interest) to water (diluent) in that order. If so, a 1:2 dilution means 1 part juice to 2 parts water, for a total of 3 parts. When the total volume is fixed at 5 ml, the proportions would be:
- For 1:2 (juice:water = 1:2): juice = 5 × (1/3) ≈ 1.67 ml; water ≈ 3.33 ml.
- For 1:5 (juice:water = 1:5): juice = 5 × (1/6) ≈ 0.83 ml; water ≈ 4.17 ml.
These are the values you would expect if the standard interpretation holds. Note that sometimes people label dilutions differently (e.g., water:juice), or may use 1:X to mean something else, so ambiguity can arise and you should check the convention given in the material. With the numbers above in mind, we can evaluate each option.

Option 1: A. 2.5 ml water & 2.5 ml juice, B. 4 ml water & 1 ml juice
- For A (2.5 water, 2.5 juice): this is a 1:1 ratio of juice:water, not 1:2. It does not match the requested 1:2 dilution under the common interpretation, which would require juice ≈ 1.67 ml and water ≈ 3.33 ml. Therefore A’s values are inconsistent with a 1:2 dilution.
- For B (4 ml water, 1 ml juice): this is a 1:4 juice:water ratio, not 1:5. The expected 1:5 would be juice ≈ 0.83 ml and water ≈ 4.17 ml, so this option for B also deviates from the 1:5 target.
- Overall, option 1 does not align with the standard 1:2 and 1:5 dilutions in a 5 ml total.

Option 2: A. 2 ml water & 3 ml juice, B. 2.5 ml water & 2.5 ml juice
- For A: water 2 ml and juice 3 ml yields a juice:water ratio of 3:2, which is 1.5:1, not 1:2. This does not satisfy a 1:2 dilution.
- For B: 2.5 ml water & 2.5 ml juice is again a 1:1 ratio, not 1:5. This also fails to meet the requested B dilution.
- Hence option 2 mismatches both targets.

Option 3: A. 1 ml water & 4 ml juice, B. 4.5 ml juice & 0.5 ml water
- For A: 1 ml water and 4 ml juice gives juice:water = 4:1, a very concentrated ratio (4:1) far from 1:2. It does not satisfy the 1:2 target.
- For B: 4.5 ml juice and 0.5 ml water yields water:juice = 0.5:4.5 = 1:9, or juice:water = 9:1, which is far from 1:5. This also deviates from the stated dilution.
- Overall, option 3 is inconsistent with both specified dilutions.

Option 4: A. 1.5 ml water & 3.5 ml juice, B. 3 ml water & 2 ml juice
- For A: 3.5 ml juice and 1.5 ml water gives juice:water = 3.5:1.5 ≈ 7:3 ≈ 2.33:1, not 1:2. This does not meet the 1:2 requirement.
- For B: 3 ml water and 2 ml juice yields juice:water = 2:3 ≈ 0.67:1, which is not 1:5. It also fails to meet the dilution target for B.
- Thus option 4 also does not correspond to the requested dilutions.

Synthesis across options: Each option attempts to allocate 5 ml into water and juice for A and B, but none of the options provide amounts that match the conventional 1:2 (juice:water) and 1:5 (juice:water) ratios in a total volume of 5 ml. If your course or lab material uses a different convention (for example, specifying water:juice rather than juice:water, or using a fixed total volume with a different interpretation of the ratio), you would need to apply that convention to compute the exact amounts. In this exercise, the given options do not align with the standard interpretation described above, so evaluating them against that standard leads to the conclusion that none are consistent with both target dilutions.

BIOL-10-20048-S25 Lab Exam 1 - Wednesday 3/19

Calculate the following dilutions: A. A 1:2 grape juice solution in a total volume of 5 ml. B. A 1:5 dilution of grape juice in a total volume of 5 ml. Dilutions Amount of Water (ml) Amount of Juice (ml) 1:2 1:5

查看解析

登录即可查看完整答案

类似问题

6 mL of a stock solution of 300 mM citrate buffer is diluted to a final volume of 30 mL.What is the final concentration of the diluted citrate buffer (in units of mM)?

You want to prepare a ten-fold dilution of a 20% dye solution. a) How much of the 20% dye do you need to use to make 1 mL total volume of the ten-fold dilution? 0.1 mL b) What will the dye concentration of the dilution be? 2%

You have a 500 µM (micromolar) solution of sucrose and would like to make 1 mL of a 100 µM solution. How many microliters (µL) of the 500 µM solution will you need to use to make 1 mL of the 100 µM solution?

In a consumer society, many adults channel creativity into buying things

Economic stress and unpredictable times have resulted in a booming industry for self-help products

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单