You have a 500 µM (micromolar) solution of sucrose and would like to make 1 mL of a 100 µM solution. How many microliters (µL) of the 500 µM solution will you need to use to make 1 mL of the 100 µM solution?

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BlackTom AI · Accepted Answer

We start by identifying the dilution relationship for preparing a desired concentration from a stock solution. The plan uses C1V1 = C2V2, where C1 is the concentration of the stock, V1 the volume to take from the stock, C2 the final concentration, and V2 the final volume.

Given: C1 = 500 µM, C2 = 100 µM, V2 = 1 mL. First convert the final volume to the same units as the concentrations, or keep track of microliters consistently: 1 mL = 1000 µL.

Apply the equation: V1 = (C2 × V2) / C1 = (100 µM × 1000 µL) / 500 µM.

Compute the numerator: 100 × 1000 = 100,000. Divide by 500: 100,000 / 500 = 200.

Thus V1 = 200 µL. This means you would pipette 200 µL of the 500 µM sucrose stock and dilute it with solvent up to a total volume of 1 mL to achieve the desired 100 µM solution.

Tips to avoid common mistakes: ensure the units of concentration cancel correctly (µM cancels) and that the final volume is expressed in the same length units as V1 (here, microliters) to keep the math straightforward. If you mixed up milliliters and microliters, you could easily obtain an incorrect volume like 0.2 mL or 200 µL, so staying consistent helps prevent errors.

W25 BIOL D006B 01Y Cell & Molecular Biology Lab 1A Pre-lab Quiz

You have a 500 µM (micromolar) solution of sucrose and would like to make 1 mL of a 100 µM solution. How many microliters (µL) of the 500 µM solution will you need to use to make 1 mL of the 100 µM solution?

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