What is the output of the following Python code?

def foo(x, y=3):
print(x+y)

foo(5)

Question

What is the output of the following Python code?

def foo(x, y=3):
    print(x+y)

foo(5)

BlackTom AI · Accepted Answer

First, I examine the function definition: def foo(x, y=3): print(x+y). Here, x is a required positional argument, and y has a default value of 3. When foo is called with a single argument, that argument is bound to x, and y takes its default value of 3.

Option 1: 'Python will report an error' — This is incorrect because the function foo is defined with a required x and an optional y with a default value. Calling foo(5) provides the required argument, so there is no error.

Option 2: '5' — This would be the result if the code printed just x, ignoring y or if y were somehow not added. However, the code prints the sum x+y, and since y defaults to 3, the printed value is not 5.

Option 3: '3' — This would correspond to printing only y or if x were missing, but in this call both values participate in the sum, so the result is not 3.

Option 4: '8' — This is the correct outcome. The function call foo(5) sets x = 5 and uses the default y = 3, so the expression x + y evaluates to 8, which is what gets printed.

In summary, the reasoning hinges on understanding default parameter values and how positional arguments bind when a default is provided. Since foo(5) supplies only x, y remains at its default of 3, yielding 5 + 3 = 8 when printed.

4510_COMP_SCI_X_0010 W03 Quiz

What is the output of the following Python code? def foo(x, y=3): print(x+y) foo(5)

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