题目
题目

25S-STATS-102B-LEC-3 Final Exam- Requires Respondus LockDown Browser

单项选择题

Given 𝐵 = [ − 1 0 1 0 1 − 1 ] , please find Cov(AX, BX).

选项
A.[ − 4 − 3 − 2 1 − 8 7 ]
B.None of these options are correct.
C.[ − 4 − 3 − 8 7 ]
D.[ 4 − 3 − 2 1 ]
E.[ − 4 − 3 − 8 7 − 2 1 ]
F.[ 8 − 7 − 2 1 ]
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标准答案
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思路分析
The question asks for Cov(AX, BX) given a matrix B = [ [-1, 0, 1], [0, 1, -1] ]. To reason about this, recall a standard identity: Cov(AX, BX) = A Cov(X) B^T, assuming X is a random vector with Cov(X) well-defined and A, B are conformable matrices. Key clarifications needed to evaluate the options: - We need the matrix Cov(X) (often denoted Σ or Cov(X)) to compute Cov(AX, BX) via the formula A Σ B^T. - We also need the matrix A to apply the left multiplication and the shapes to match (A must have rows corresponding to the dimension of AX and columns matching the number of rows of X, similarly for B with BX). - In the provided data, A is not given, nor is Cov(X) specified. Without these, Cov(AX, BX) cannot be numerically determined. Any concrete numeric option would implicitly assume a specific A and Σ, which aren’t provided here. Now, let’s examine the options in light of this: Option 1: [ −4 −3 −2 1 −8 7 ] This appears to be a......Login to view full explanation

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