题目
25S-STATS-102B-LEC-3 Final Exam- Requires Respondus LockDown Browser
单项选择题
Given 𝐵 = [ − 1 0 1 0 1 − 1 ] , please find Cov(AX, BX).
选项
A.[
−
4
−
3
−
2
1
−
8
7
]
B.None of these options are correct.
C.[
−
4
−
3
−
8
7
]
D.[
4
−
3
−
2
1
]
E.[
−
4
−
3
−
8
7
−
2
1
]
F.[
8
−
7
−
2
1
]
查看解析
标准答案
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思路分析
The question asks for Cov(AX, BX) given a matrix B = [ [-1, 0, 1], [0, 1, -1] ]. To reason about this, recall a standard identity: Cov(AX, BX) = A Cov(X) B^T, assuming X is a random vector with Cov(X) well-defined and A, B are conformable matrices.
Key clarifications needed to evaluate the options:
- We need the matrix Cov(X) (often denoted Σ or Cov(X)) to compute Cov(AX, BX) via the formula A Σ B^T.
- We also need the matrix A to apply the left multiplication and the shapes to match (A must have rows corresponding to the dimension of AX and columns matching the number of rows of X, similarly for B with BX).
- In the provided data, A is not given, nor is Cov(X) specified. Without these, Cov(AX, BX) cannot be numerically determined. Any concrete numeric option would implicitly assume a specific A and Σ, which aren’t provided here.
Now, let’s examine the options in light of this:
Option 1: [
−4
−3
−2
1
−8
7
]
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