Compare the magnitude of the electric force on +1 C and -2 C of charges:

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Consider the setup: two charges, +1 C and -2 C, exert forces on each other. The magnitude of the force between two point charges is given by F = k |q1 q2| / r^2, which depends on the product of the magnitudes of the charges and the separation distance, not on the sign of the charges.

Option a: 'The force on +1 C is greater because it is a positive charge.' This is incorrect because the sign of the charge does not determine the magnitude of the force; the magnitudes depend on |q1 q2| and the distance. Since |+1 C| × |-2 C| = 2 C^2, the magnitude is the same on both charges.

Option b: 'Both charges have the force of the same magnitude.' This is correct under the standard two-body Coulomb interaction: the force on each charge has the same magnitude (Newton's third law), though the directions are opposite.

Option c: 'There is not enough information because the distance between the charges is not given.' While the exact numeric value of the force depends on the separation r, the statement about the relative magnitudes on the two charges is still that they are equal in magnitude for any given separation r. The lack of a specific distance does not change the conclusion about equality of magnitudes.

Option d: 'The force on -2 C is greater because it has a greater value of charge.' This is incorrect because the force magnitude depends on the product |q1 q2|, not on which individual charge is larger when comparing the force on each of the two charges; both experience the same magnitude force in opposite directions when the distance is the same.

UCIC 202503 PHYS101 Quiz 9

Compare the magnitude of the electric force on +1 C and -2 C of charges:

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