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题目
题目
单项选择题

Schedule II Controlled Substances (CLO 1):

选项
A.can be telephoned in with no more than 5 prescriptions in 6 months.
B.can be prescribed by written prescription only.
C.cannot be prescribed.
D.can be purchased over the counter.
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标准答案
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思路分析
Here is the question and the answer options restated for clarity: Question: Schedule II Controlled Substances (CLO 1): Options: - can be telephoned in with no more than 5 prescriptions in 6 months. - can be prescribed by written prescription only. - cannot be prescribed. - can be purchased over the counter. Now, let's analyze each option in turn: Option 1: "can be telephoned in with no more than 5 prescriptions in 6 months." This statement is inaccurate......Login to view full explanation

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Schedule III Controlled Substances (CLO I):  

2. Match the active ingredient with the historical development that best discusses the drug issue it mediates.  Each answer option is only used once. 1: Dextromethorphan 2: Pseudoephedrine 3: Codeine

Controlled substances have a "Schedule" classification due to risk of abuse. Schedule One indicates no medical use of the medication due to risks of dependence whereas Schedule Five includes medications with the least risk of abuse.

Question text Each student below analyzes a proposed trigonometric expression and explains their reasoning.Match each student’s reasoning to the explanation that best fits their thinking. Student 1:I was asked to evaluate .I tested it using and , and the two sides were not equal. I tried other values too and got the same result. I believe this expression is never true.Answer 1 Question 23[select: , The student was correct; the expression is never true. Multiple test cases using different values always yield unequal results., The student analysis was incorrect; the expression is always true because it is a valid trigonometric identity., The student analysis was incorrect; the expression is sometimes true. It holds for some distinct values of x and y, but is unequal for other values.] Student 2:I was asked to verify .I recognized the numerator as based on the Pythagorean identity, so the left side of the expression becomes .I now realize this means the expression is never true.Answer 2 Question 23[select: , The student's analysis was incorrect; the expression is always true because the numerator is equivalent to sin^2(x), not -sin^2(x)., The student's analysis was incorrect; the expression is sometimes true because it holds for specific values of x, but fails for most other values., The student was correct; the expression is never true since the left side simplifies to -1, which is never equal to the right side.] Student 3:I was asked to evaluate .I tested it using , and both sides came out equal. I concluded the expression is always true.Answer 3 Question 23[select: , The student was correct; the expression is always true for all values of x ., The student analysis was incorrect; the expression is sometimes true; when different values for x are tested, the two sides are not equal., The student analysis was incorrect; the expression is never true for any value of x.]

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