What is the output of the following code snippet if count contains 56?
if count % 2 == 0 :
print("Count is an even number")
else :
print("Count is an odd number")

Question

What is the output of the following code snippet if count contains 56?
if count % 2 == 0 :
   print("Count is an even number")
else :
   print("Count is an odd number")

BlackTom AI · Accepted Answer

Consider what the code does with a given count value. The condition checks whether count % 2 == 0, which means it tests if count is divisible by 2 without a remainder.
Option 1: 'Count is an even number' would be printed if the condition is true. Since count is 56, 56 % 2 equals 0, so the condition holds and the program executes the first print statement.
Option 2: 'Count is an odd number' would require the condition to be false (i.e., count % 2 != 0). That is not the case for 56, making this option incorrect.
Option 3: 'Nothing, there is a syntax error' claims there is a syntax problem. The code snippet uses proper Python syntax: the colon after the if, the indentation for the print statement, and the else block are all valid here, so there is no syntax error.
Option 4: 'Nothing, the program runs but does not print any output' suggests no print occurs. In this structure, exactly one of the print statements will execute, so this option is false as the program does produce output.
In summary, the correct behavior is determined by the parity check; since 56 is even, the program prints the first message and none of the other statements apply.

Fal25_CS003C_74229 Ch. 3 Pre-Quiz (Remotely Proctored)

What is the output of the following code snippet if count contains 56? if count % 2 == 0 : print("Count is an even number") else : print("Count is an odd number")

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