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Question at position 8 Consider the following joint distribution of X and Y. [table] X | Y | P(X=x,Y=y) 3 | 10 | 0.18 3 | 15 | 0.12 3 | 18 | 0.04 4 | 10 | 0.15 4 | 15 | 0.19 4 | 23 | 0.01 5 | 15 | 0.07 5 | 18 | 0.11 5 | 23 | 0.13 [/table] What is E(Y|X=4)E(Y|X=4)? Round your answer to 3 decimal places.AnswerConsider the following joint distribution of X and Y. [table] X | Y | P(X=x,Y=y) 3 | 10 | 0.18 3 | 15 | 0.12 3 | 18 | 0.04 4 | 10 | 0.15 4 | 15 | 0.19 4 | 23 | 0.01 5 | 15 | 0.07 5 | 18 | 0.11 5 | 23 | 0.13 [/table] What is E(Y|X=4)E(Y|X=4)? Round your answer to 3 decimal places.[input]BlackTom题目解析

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We are given a joint distribution table for X and Y and asked to find E(Y | X = 4). First, identify all outcomes that have X = 4. From the table, these are: - (X=4, Y=10) with P = 0.15 - (X=4, Y=15) with P = 0.19 - (X=4, Y=23) with P = 0.01 Next, compute the......Login to view full explanation

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According to an expert, the inflation rate and the cash rate (the interest rate set by the Reserve Bank of Australia) in Australia in the next quarter is governed by the following joint probability density function: \[ \begin{matrix} \text{cash rate } \downarrow \diagdown \text{inflation rate } \longrightarrow & 1.00\% & 1.25\% & 1.50\% \\ \hline 0.05\% & 0.06 & 0.10 & 0.00 \\ 0.10\% & 0.04 & 0.50 & 0.10 \\ 0.25\% & 0.00 & 0.10 & 0.10\end{matrix} \] According to this expert, what is the expected value of the inflation rate conditional on cash rate staying at \(0.10\%\) next quarter? Do all calculations to the highest precision and then round your final answer to two decimal points and enter it in percentage points but without the % sign.

Question at position 2 Consider two variables, Y and X. Y is a continuous random variable, while X is a discrete random variable that takes only values 0 and 1. In particular, P(X=0)=P(X=1)=0.5P(X=0) = P(X=1) = 0.5. Suppose that you know E(Y)=4.25E(Y) = 4.25. If E(Y|X=0)=5E(Y|X=0) = 5, what is E(Y|X=1)E(Y|X=1)? Enter your answer as an exact number.AnswerConsider two variables, Y and X. Y is a continuous random variable, while X is a discrete random variable that takes only values 0 and 1. In particular, P(X=0)=P(X=1)=0.5P(X=0) = P(X=1) = 0.5. Suppose that you know E(Y)=4.25E(Y) = 4.25. If E(Y|X=0)=5E(Y|X=0) = 5, what is E(Y|X=1)E(Y|X=1)? Enter your answer as an exact number.[input]BlackTom题目解析

Following the question above, what is the conditional expectation of 𝑋 1 given 𝑋 2 = 1 ?

If the conditional variance for tomorrow's return is 0.0004, 𝑉 𝑎 𝑅 𝑡 ( 𝑅 𝑡 + 1 ) = ( 0.02 ) 2 = 0.0004 , then the conditional expectation for tomorrow's return is 2% or -2%.

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