Question at position 4 A school implemented a new reading program aimed at enhancing students' literacy skills. After participating in the program, a group of 50 students' reading scores were measured. The mean reading score for this group was 90, and the standard deviation of scores was 7. The known population mean for students without the reading program is 80. Calculate Cohen's d to demonstrate the substantial positive impact of the new reading program on students' reading scores. Calculate Cohen's d to assess the impact of the memory enhancement program on participants' memory scores. Round your answer to 2 decimal places. Question Blank 1 of 2[input] Now, interpret what this means. Question Blank 2 of 2[input]

Question

Question at position 4 A school implemented a new reading program aimed at enhancing students' literacy skills. After participating in the program, a group of 50 students' reading scores were measured. The mean reading score for this group was 90, and the standard deviation of scores was 7. The known population mean for students without the reading program is 80. Calculate Cohen's d to demonstrate the substantial positive impact of the new reading program on students' reading scores. Calculate Cohen's d to assess the impact of the memory enhancement program on participants' memory scores. Round your answer to 2 decimal places. Question Blank 1 of 2[input] Now, interpret what this means. Question Blank 2 of 2[input]

BlackTom AI · Accepted Answer

The question presents two tasks: (1) compute Cohen's d for reading scores and (2) compute Cohen's d for memory scores, followed by interpretation. We will evaluate each part in turn, noting any missing information when relevant.

Part 1 (reading scores): The data given are: sample mean = 90, population mean (baseline) = 80, standard deviation = 7, and sample size n = 50. Cohen's d is calculated as (mean − population mean) / standard deviation. Substituting the values gives (90 − 80) / 7 = 10 / 7 ≈ 1.4286. When rounded to two decimals, this is 1.43. This value reflects a very large effect size, suggesting the new reading program is associated with a substantial improvement in reading scores relative to the baseline.

Part 2 (memory scores): The prompt asks to calculate Cohen's d for the memory enhancement program but provides no memory scores, no baseline mean, and no standard deviation. Without those three components (mean of the treated group, mean of the control/baseline group, and the appropriate variability measure), it is impossible to compute a Cohen's d. Therefore, any numeric result for the memory program would be unsupported by the data given, and we cannot produce a valid value here. If you had the memory group mean, the control mean, and the standard deviation (or a pooled SD) along with the sample size, you could compute d in the same fashion as above.

Interpretation of the reading result: A Cohen's d of approximately 1.43 indicates a large positive effect; the average student who experienced the reading program outperformed the baseline by a substantial margin relative to the observed variability in scores. In educational research, such a magnitude is typically considered a strong, practically meaningful improvement. Comparisons to typical educational effect sizes should note that context matters, but 1.43 generally signifies a large effect.

Note on the blank/undefined portion: Because the answer options are empty for this item, there is no alternative choice to evaluate against. The only concrete computation we can perform from the provided data is the reading-score d = 1.43, and the memory-score part remains undefined due to missing data.

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A sample is selected from a population with μ = 46, and a treatment is administered to the sample. After treatment, the sample mean is M = 48 with a sample variance of s2 = 16. Based on this information, what is the value of Cohen’s d?

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