A set of data has the following characteristics:

- Scores smallest place value are hundredths,

- The range is 72,

- It has been decided to use 7 intervals.

What is the interval or class width to be used?

Question

A set of data has the following characteristics:

- Scores smallest place value are hundredths,

- The range is 72,

- It has been decided to use 7 intervals.

What is the interval or class width to be used?

BlackTom AI · Accepted Answer

Start by identifying the given values and what is being asked. The data set has a stated range of 72, and the plan is to use 7 intervals (classes).
Next, compute the interval width by dividing the range by the number of intervals: 72 ÷ 7 = 10.285714...
Since the problem mentions that the smallest place value of scores is the hundredth (two decimal places), you should express the class width to two decimals. Rounding 10.285714... to two decimals gives 10.29.
A useful cross-check is to recognize that using 7 equal-width intervals with a width of about 10.29 will cover the total range of 72 when the interval endpoints are set appropriately, maintaining the prescribed number of intervals.
If you instead kept the width as the exact fraction 72/7, you would have 10.285714..., which would conflict with the hundredths requirement, so rounding to 10.29 aligns with the stated precision.
No other alternative numbers are suggested in the prompt, so the key steps involve dividing the range by the number of intervals and applying the required precision to adhere to the data’s hundredth-place rule.

BU-STAT-2103-751-49510-202503 Understanding frequency distributions - Deciding number of intervals and interval widths (Practice)

A set of data has the following characteristics: - Scores smallest place value are hundredths, - The range is 72, - It has been decided to use 7 intervals. What is the interval or class width to be used?

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