Consider the equilibrium system

C(s) + CO2(g) ⇔2CO(g)
If C is removed, the equilibrium will _____, and if CO is added, the equilibrium will _____.

Question

Consider the equilibrium system

C(s) + CO2(g) ⇔2CO(g)
If C is removed, the equilibrium will _____, and if CO is added, the equilibrium will _____.

BlackTom AI · Accepted Answer

Let's parse the given equilibrium: C(s) + CO2(g) ⇔ 2 CO(g). The key point here is that C is a solid; in equilibrium expressions for heterogeneous equilibria, the activity of a pure solid is taken as 1 and does not appear in the expression. Therefore, changes to the amount of C(s) do not affect the position of equilibrium as far as the gas-phase species (CO2 and CO) are concerned, because the equilibrium constant K depends on the activities of CO(g) and CO2(g) only.

Option analysis:
- If C(s) is removed: Since C(s) is a solid and its activity is effectively constant (and does not appear in K), removing some of the solid does not change the relationship between CO2 and CO at equilibrium. The system should show no shift in the gas composition because the driving force for the reaction to proceed towards either side is not altered by the presence or absence of a solid reactant. Therefore, the equilibrium will be unchanged with respect to the gas-phase concentrations.

- If CO is added: Adding more CO(g) increases the activity (concentration) of CO. According to Le Chatelier's principle, the system will respond by consuming CO to reduce the disturbance. In this reaction, consuming CO means shifting the equilibrium to the left to form CO2(g) and C(s). So the shift is toward the left, i.e., toward CNF formation of CO2 and the solid carbon.

In summary, removing the solid C(s) does not change the equilibrium position in terms of gas species (be unchanged), while adding CO(g) drives the system to the left to offset the added CO by converting it to CO2 and C(s).

CHM-1020-LD01.2025SU Quiz 3-Equilibrium

Consider the equilibrium system C(s) + CO2(g) ⇔2CO(g) If C is removed, the equilibrium will _, and if CO is added, the equilibrium will _.

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