A block of wood with dimensions of length = 1.6m, width = 0.4m and height = 1m, is placed in water, what is the buoyant force? The density of water is 1000kg/m3. Answer to 1 decimal places and only put in the numerical value. Do not write the unit in your answer.

Question

A block of wood with dimensions of length = 1.6m, width = 0.4m and height = 1m, is placed in water, what is the buoyant force? The density of water is 1000kg/m3. Answer to 1 decimal places and only put in the numerical value. Do not write the unit in your answer.

BlackTom AI · Accepted Answer

We start by identifying the principle needed: the buoyant force equals the weight of the fluid displaced (Archimedes’ principle). The displaced volume is the volume of the block that is submerged, which for a fully submerged rectangular block is simply its total volume.

Step 1: Compute the volume of the block.
Volume V = length × width × height = 1.6 m × 0.4 m × 1.0 m = 0.64 m³.

Step 2: Use the buoyant force formula.
Buoyant force F_b = ρ × g × V, where ρ is the density of water and g is the acceleration due to gravity.
Given ρ = 1000 kg/m³ and g ≈ 9.8 m/s².

Step 3: Substitute the values.
F_b = 1000 × 9.8 × 0.64.

Step 4: Perform the multiplication.
First, 1000 × 0.64 = 640; then 640 × 9.8 = 6272 N.

Step 5: Apply the requested precision.
Expressing to 1 decimal place yields 6272.0. Since the problem asks for just the numerical value without units, the result is 6272.0.

FFP001 Threshold Quiz 5 | LA020

A block of wood with dimensions of length = 1.6m, width = 0.4m and height = 1m, is placed in water, what is the buoyant force? The density of water is 1000kg/m3. Answer to 1 decimal places and only put in the numerical value. Do not write the unit in your answer.

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