List the following molecules in order of increasing bond order: 1. C=C 2. C-C 3. CΞC

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BlackTom AI · Accepted Answer

To tackle this question, let's recall the bond orders for the three given bonds: a single C–C bond has a bond order of 1, a C=C double bond has a bond order of 2, and a C≡C triple bond has a bond order of 3.

Option a: '2, 1, 3'. This sequence lists the bonds in increasing order of bond strength as 2 (C=C), then 1 (C–C), then 3 (C≡C). Since 1 < 2 < 3, this arrangement correctly increases in bond order.

Option b: '1, 3, 2'. Here the sequence starts with 1, then jumps to 3, and ends with 2. This is not a monotonic increase because 3 > 2, so the order is not strictly ascending.

Option c: '3, 1, 2'. This starts with the highest bond order (3) and then goes down to 1 and 2, which is a decreasing sequence, not increasing.

Option d: '1, 2, 3'. This presents a perfect increasing sequence, but note the actual list corresponds to C–C (1), C=C (2), and C≡C (3). If interpreted as the order of the three given molecules, this would imply the second item comes before the first in bond order, which contradicts the known bond orders.

Option e: '3, 2, 1'. This is a strictly decreasing sequence of bond orders, not increasing.

Option f: '2, 3, 1'. This starts with 2, then increases to 3, and then drops to 1, which fails the requirement for a consistently increasing order.

In summary, the only option that preserves a consistent increase in bond order from smallest to largest among the three bonds is the sequence that goes from 1 to 2 to 3. Each distractor either reverses the order or introduces a non-monotonic progression, illustrating common misconceptions about how bond order translates to ordering of bond types.

List the following molecules in order of increasing bond order: 1. C=C 2. C-C 3. CΞC

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