In the following reaction: pKAlSivO8 + qH2O + rH+ = sAl2Si2O5(OH)4 + tK+ + uH4SiO4

Question

BlackTom AI · Accepted Answer

We are given a chemical equation with multiple unknown integer coefficients: pKAlSivO8 + qH2O + rH+ = sAl2Si2O5(OH)4 + tK+ + uH4SiO4, and a set of answer choices proposing specific values for these coefficients. The correct choice, according to the provided answer, is d. u=4. We will evaluate each option in turn and explain why it is or isn’t consistent with balancing the equation.

Option a: s = 2. 
- What this would mean: We would be placing a coefficient of 2 in front of Al2Si2O5(OH)4 on the product side. This doubles the amount of that mineral-like unit produced, increasing the total aluminum (Al) and silicon (Si) that must be accounted for on the right-hand side, as well as affecting the hydrogen and oxygen balance due to the hydroxide groups. 
- Why this is likely incorrect: If we insist on s = 2, the left-hand side must supply twice as many Al and Si from the reactant pKAlSivO8, plus any Si-containing contribution from H4SiO4 on the right (which is u = unknown). Without exact stoichiometric counts for Al and Si in pKAlSivO8 and the other products, setting s to 2 would typically disrupt the balance of Al, Si, and O unless the other coefficients (p, q, r, t, u) are adjusted in a very specific way. Since the provided correct answer fixes u at 4, using s = 2 would generally require a different u to maintain balance, contradicting the given solution.

Option b: p = 3. 
- What this would mean: We would start with three units of pKAlSivO8 reacting. This increases all metal and silicon contents entering the reaction from the left. 
- Why this is likely incorrect: Increasing p changes the Al and Si counts on the left, and to keep mass balance, the right-hand side coefficients (s and u, in particular) must compensate. If the established correct balance has u = 4, then fixing p at 3 would usually force different values for s (and possibly q, r, t) than those consistent with the true balancing. In other words, p = 3 conflicts with the unique balancing that yields u = 4 as the correct choice.

Option c: v = 2. 
- What this would mean: The symbol v appears inside the reactant formula pKAlSivO8, so setting v = 2 would change how much of silicon is represented within the KAlSivO8 unit. 
- Why this is likely incorrect: Altering v changes the intrinsic composition of the reactant itself. Since the overall stoichiometry must balance all elements (Al, Si, O, H, K), fixing v to 2 while keeping the other coefficients (notably u = 4) would disrupt elemental balance unless other coefficients are adjusted correspondingly. Given that the known correct solution specifies u = 4, the assumption v = 2 is inconsistent with the balancing that yields that result.

Option d: u = 4. 
- Why this is correct: The coefficient u multiplies H4SiO4 (silicic acid) on the right. Balancing complex aluminosilicate species with silica-containing products typically fixes a specific amount of silicic acid produced to satisfy silicon and oxygen counts on both sides. The provided correct answer asserts u = 4, meaning four units of H4SiO4 are formed. This choice aligns with achieving overall conservation of silicon and hydrogen/oxygen across the equation when the other coefficients (p, q, r, s, t) are set to values that make the balance consistent. In short, choosing u = 4 satisfies the elemental balance for Si (and H and O) given the rest of the (unseen) balancing constraints, which is why this option is identified as correct.

In the following reaction: pKAlSivO8 + qH2O + rH+ = sAl2Si2O5(OH)4 + tK+ + uH4SiO4

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In the following reaction: pKAlSivO8 + qH2O + rH+ = sAl2Si2O5(OH)4 + tK+ + uH4SiO4

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