The following reaction is balanced.

SiO2(s) + 3 C(s) ⟶ SiC(s) + 2 CO(g)

Question

The following reaction is balanced.

SiO2(s) + 3 C(s) ⟶ SiC(s) + 2 CO(g)

BlackTom AI · Accepted Answer

Consider the reaction as written: SiO2(s) + 3 C(s) ⟶ SiC(s) + 2 CO(g).

Option 1 (True): The balance of elements appears consistent. Silicon: 1 atom on the left (SiO2) and 1 atom in the product (SiC). Oxygen: 2 O atoms on the left (in SiO2) and 2 O atoms on the right (in 2 CO molecules). Carbon: 3 C atoms on the left (3 C) and 1 C in SiC plus 2 C in 2 CO on the right, totaling 3 C. Hence, all elements are conserved, suggesting the equation is balanced.

Option 2 (False): If one were to claim it is unbalanced, they might look for discrepancies in elements or a mismatch in the total number of atoms. However, in this case, a quick tally shows that each element appears with the same count on both sides: Si (1 in SiO2 vs 1 in SiC), O (2 in SiO2 vs 2 in CO×2), and C (3 on the left vs 1 in SiC + 2 in CO×2 = 3 on the right). Any suggestion of imbalance would stem from overlooking the right-hand side carbon distribution or miscounting oxygen, but careful accounting confirms the counts match.

In-depth check of atom balance:
- Silicon: left 1, right 1 → balanced
- Oxygen: left 2, right 2 → balanced
- Carbon: left 3, right 1 (in SiC) + 2 (in CO) = 3 → balanced

Therefore, there is no violation of the conservation of mass for this reaction as written.

CHEM 110 Section 3 (PM) SP25 Pre-Lecture Quiz 38 C15-3-4

The following reaction is balanced. SiO2(s) + 3 C(s) ⟶ SiC(s) + 2 CO(g)

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