A car is initially at rest at time t=0. 17.2 seconds later, the car has reached a speed of 16 m/s. What was the magnitude of the car's average acceleration over this stretch of time?

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Question

A car is initially at rest at time t=0. 17.2 seconds later, the car has reached a speed of 16 m/s. What was the magnitude of the car's average acceleration over this stretch of time?

a
=
_
_
_
_
_
_
m
/
s
2

BlackTom AI · Accepted Answer

A car starts from rest, so initial velocity v_i = 0 m/s. The final velocity after 17.2 s is v_f = 16 m/s. The average (constant) acceleration over this interval is defined by a_avg = (v_f − v_i) / Δt.

Plugging in the values: Δt = 17.2 s, v_f − v_i = 16 m/s − 0 m/s = 16 m/s.

Therefore, a_avg = 16 m/s ÷ 17.2 s ≈ 0.931 m/s^2.

For reporting with two significant figures, this can be written as 0.93 m/s^2. The units come from velocity (m/s) divided by time (s), yielding m/s^2.

Key steps to understand: recognize that starting from rest implies v_i = 0, identify the time interval over which the velocity changes, apply the definition of average acceleration as the rate of change of velocity, and perform the division with proper attention to units and significant figures.

A car is initially at rest at time t=0. 17.2 seconds later, the car has reached a speed of 16 m/s. What was the magnitude of the car's average acceleration over this stretch of time? a = _ _ _ _ _ _ m / s 2

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