How many protons, neutrons, and electrons are in one atom of 67Zn ?

Question

How many protons, neutrons, and electrons are in one atom of 67Zn ?

BlackTom AI · Accepted Answer

We start by identifying the key facts needed: zinc has an atomic number of 30, which means 30 protons in every atom. The mass number given is 67, so the number of neutrons is mass number minus atomic number: 67 − 30 = 37 neutrons. In a neutral atom, the number of electrons equals the number of protons, so there are 30 electrons. Now evaluate each option:

Option 1: 67 protons, 30 neutrons and 30 electrons. This is incorrect because the atom cannot have 67 protons for zinc (atomic number is 30). The mass number 67 includes the protons and neutrons combined, so 67 protons would imply an entirely different element.

Option 2: 37 protons, 30 neutrons and 37 electrons. This misstates the proton count (should be 30, not 37) and also assigns 37 electrons, which would imply a highly charged ion rather than a neutral atom. It confuses the fundamental identity with incorrect subatomic counts.

Option 3: 30 protons, 67 neutrons and 40 electrons. Here the neutron count is wrong (neutrons should be 37, not 67), and the electron count (40) does not match the proton count for neutrality. This option mixes up mass composition and charge balance.

Option 4: 30 protons, 37 neutrons and 30 electrons. This aligns with the known atomic number (30 protons), the given mass number giving 37 neutrons, and a neutral zinc atom having 30 electrons. Each count matches the standard relationships: protons define the element, neutrons + protons make up the mass number, and electrons balance protons in a neutral atom.

In summary, the only option that satisfies the atomic number, mass number, and charge neutrality consistently is the one with 30 protons, 37 neutrons, and 30 electrons.

How many protons, neutrons, and electrons are in one atom of 67Zn ?

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