The term 'degenerate' is used to describe atomic orbitals which:

Question

BlackTom AI · Accepted Answer

Consider the concept being tested: degeneracy of atomic orbitals.
Option a: "are equal in energy". This is the core idea of degeneracy in atomic orbitals—orbitals that share the same energy level are degenerate. When two or more orbitals have the same energy, electrons can occupy them without a difference in energy, hence degeneracy.
Option b: "have the same value for n". Having the same principal quantum number n does not guarantee degeneracy. Orbitals with the same n can have different energies depending on the subshell (l) and magnetic quantum number (m_l); for example, 2s and 2p orbitals do not share identical energies in many atoms. Therefore this statement is incorrect as a general rule.
Option c: "do not contain electrons". Degeneracy relates to energy levels and orbital shapes, not to whether an orbital is occupied. An orbital can be degenerate and still contain electrons or be empty, so this option is not an accurate definition of degeneracy.
Option d: "contain two electrons". The statement implies a fixed electron count per degenerate orbital, which is false. Degeneracy concerns energy equality among orbitals, not how many electrons they hold. Orbitals can be singly occupied, doubly occupied, or empty regardless of degeneracy.
In summary, the only option that correctly captures the intended meaning of degeneracy in atomic orbitals is that degenerate orbitals are those that are equal in energy, while the other options misstate or confuse the concept with occupancy, quantum numbers, or energy relationships.

CHM1051 MUM S2 2025 CHM1051 Practice Exam 2

The term 'degenerate' is used to describe atomic orbitals which:

查看解析

登录即可查看完整答案

类似问题

Consider the following orbital in the n=5 shell: This orbital has [Fill in the blank] angular node(s) and [Fill in the blank] radial node(s). (Input numbers only.)

Orbitals with larger principal quantum number (n) have a smaller size.

The atomic orbital for an electron in an atom with the quantum numbers n = 4, l = 3, ml = 0, ms = – 1 2 is

Which figure represents the orbital in which the highest energy electron resides for the ground-state Sn+ (Z = 50) ion?

Which of the period 4 orbitals below is a 3dyz orbital?

The 2s orbital of potassium is more stable than the 2p orbital even though the 2p orbital has its maximum electron density closer to the nucleus. The reason for this higher stability is:

An atomic orbital can contain up to how many electrons?

Question textBased on the following orbital shapes, identify the subshell each orbital belongs toi. Answer 1 Question 26[select: , s, p, d, f]ii. Answer 2 Question 26[select: , s, p, d, f]iii. Answer 3 Question 26[select: , s, p, d, f]iv. Answer 4 Question 26[select: , s, p, d, f]

更多留学生实用工具

考试浏览器助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单