题目
多项填空题
For the series 9∑n=2(7−3n)\displaystyle\sum^9_{n=2}(7-3n) a=a= [Fill in the blank], d=d= [Fill in the blank], 9∑n=2(7−3n)=\displaystyle\sum^9_{n=2}(7-3n)= [Fill in the blank], (type a number only in each box)
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标准答案
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思路分析
We start by identifying the terms of the series t_n = 7 − 3n for n = 2, 3, ..., 9.
First blank (a): to get the first term of the sequence, plug in n = 2:
t_2 = 7 − 3(2) = 7 − 6 = 1.
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