题目
题目

CHM1051 MUM S1 2025 Week 12: Weekly quiz (1%)

单项选择题

For a chemical reaction, the rate constant at 42.0 °C is 0.00395 s-1, while the rate constant at 67.4 °C is 0.0133 s-1. Calculate the value of the energy of activation, in kilojoules.

选项
A.a. 42.65 kJ
B.b. 1.13 kJ
C.c. 0.421 kJ
D.d. 18.5 kJ
E.e. 0.617 kJ
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标准答案
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思路分析
The question asks us to determine the activation energy Ea from two rate constants at different temperatures, which points us to the Arrhenius relationship k = A e^{-Ea/(RT)}. First, identify the temperatures in Kelvin: T1 = 42.0 °C = 315.15 K, T2 = 67.4 °C = 340.55 K. The corresponding rate constants are k1 = 0.00395 s^-1 and k2 = 0.0133 s^-1. Use the logarithmic form of the Arrhenius equation for two temperatures: ln(k2/k1) = Ea......Login to view full explanation

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