The graph shows the speed at which a remote controlled toy helicopter travels during a test flight along a straight flight path. What is the acceleration (in m s-2) of the helicopter during the first t1 = 9.8 seconds, if it reached a maximum speed of 8.3 m s-1?

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BlackTom AI · Accepted Answer

To find the acceleration during the first 9.8 seconds, focus on the portion of the speed-time graph where the speed rises from 0 to its maximum.

- The helicopter starts from rest, so initial speed v0 = 0 m/s.
- After t1 = 9.8 s, the speed reaches a maximum of v = 8.3 m/s.
- Since the speed increases linearly during this interval (the graph shows a straight ramp), the acceleration a is constant and given by a = Δv / Δt.

Calculate the change in speed: Δv = v − v0 = 8.3 m/s − 0 m/s = 8.3 m/s.

Compute the acceleration: a = Δv / Δt = 8.3 m/s ÷ 9.8 s ≈ 0.8469 m/s^2.

Rounding to three significant figures, the acceleration during the first 9.8 s is approximately 0.847 m/s^2.

Notes: This uses the basic kinematics relation for constant acceleration during a straight-line speed-up, and assumes the ramp is linear as indicated by the straight line on the speed-time graph.

MUF0121 Physics Unit 1 - Semester 2, 2025 2.10 Graphical analysis of motion

The graph shows the speed at which a remote controlled toy helicopter travels during a test flight along a straight flight path. What is the acceleration (in m s-2) of the helicopter during the first t1 = 9.8 seconds, if it reached a maximum speed of 8.3 m s-1?

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