The graph shows the speed at which a remote controlled toy helicopter travels during a test flight along a straight flight path. What is the acceleration (in m s-2) of the helicopter during the first t1 = 7.9 seconds, if it reached a maximum speed of 10.0 m s-1?

Question

BlackTom AI · Accepted Answer

To find the acceleration during the first interval, focus on how velocity changes over time in the initial ramp.

- The helicopter starts from rest (v = 0 m/s) at the beginning of the flight path.
- It linearly increases to a maximum speed of 10.0 m/s over a time interval of t1 = 7.9 s, as suggested by the triangular ramp in the graph during the acceleration phase.
- With linear acceleration, the acceleration a is the slope of the velocity-time graph, given by a = Δv / Δt.

Compute the change in velocity: Δv = 10.0 m/s − 0 m/s = 10.0 m/s.
Compute the time interval: Δt = 7.9 s.

Thus, a = Δv / Δt = 10.0 / 7.9 ≈ 1.265823... m/s^2.

Rounding to three significant figures in line with the given data yields a ≈ 1.27 m/s^2.

So, the acceleration during the first 7.9 s is about 1.27 m/s^2.

The graph shows the speed at which a remote controlled toy helicopter travels during a test flight along a straight flight path. What is the acceleration (in m s-2) of the helicopter during the first t1 = 7.9 seconds, if it reached a maximum speed of 10.0 m s-1?

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