EM_MNS1b Week 8 Assessment

Assessment Using L'Hospital rule limx→1x3+x−2x2−3x+2=limx→13x2+12x−3=limx→16x2=3 \lim_{x\to 1} \frac{x^3+x-2}{x^2-3x+2} = \lim_{x\to 1} \frac{3x^2+1}{2x-3} = \lim_{x\to 1} \frac{6x}{2} = 3