What is the output of the following code? int i = 2; int j = 4; while (i

Question

What is the output of the following code? int i = 2; int j = 4; while (i < j) {
i++; j--; }
MessageBox.Show(i.ToString());

BlackTom AI · Accepted Answer

We start with i = 2 and j = 4. The loop condition is while (i < j).

Option a. 3
- In the first (and only) iteration, i is incremented to 3 and j is decremented to 3. After this iteration, the loop condition (i < j) becomes (3 < 3), which is false, so the loop stops. The final value of i is 3, which will be shown.

Option b. 5
- To reach 5, i would have to be incremented twice more without j crossing over. However, after the first iteration both i and j become 3, making the loop condition false immediately, so i cannot reach 5.

Option c. 4
- Starting at i = 2, the only modification inside the loop is i++, which increases i by 1 per iteration. Since the loop runs exactly once (due to i == j after the first iteration), i would be 3 at the end, not 4. Therefore 4 is not correct.

Option d. Error
- There is no runtime or compile-time error in this snippet. The code uses valid operations on integers and a standard while loop, so the execution proceeds as described above.

Summary: The loop runs a single time, updating i from 2 to 3 and j from 4 to 3, then stops. The shown value corresponds to i after the loop ends, which aligns with the behavior described for option a.

Introduction To Object Oriented Programming (082025-CMM)

What is the output of the following code? int i = 2; int j = 4; while (i < j) { i++; j--; } MessageBox.Show(i.ToString());

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