For this activity, you will send wave pulses down a string with different boundary conditions (i.e., fixed-fixed and fixed-loose) and investigate their transit and interference behavior. Set the wave driver to “Pulse” (upper-left corner), click the Pause Button and then the Restart Button. Then, adjust the simulation's settings as follows: Set the Amplitude to 0.75 cm. Set the Pulse Width to 0.2s Set Damping to None. Set Tension to High. Using the tools listed in the lower-right corner of the simulation (e.g., rulers, timer, etc.), determine which of the following statements are true. (I recommend using the Slow Motion mode for this activity.) Select all true statements. Answering this question requires you to time the wave pulses precisely. I recommend using the following procedure to “trigger” the timer to the first pulse--- that is, start the timer from 0:00 seconds when you pulse the generator for the first time. Ensure the simulation is paused. Reset the timer by clicking the Timer Reset Button. Click the Timer Play Button to “arm” the timer. Pulse the generator. The timer should start simultaneously.

Options

A.A pulse takes 2.4 seconds to make a round trip on this string (i.e., to travel from the wave driver, down the string, and back to the wave driver.)

B.In one round trip on this string, the pulse traverses a distance of 7.6 m.

C.The wavespeed for the string is about 0.06 m/s.

D.When a pulse reflects off a fixed end, the pulse inverts.

E.When a pulse reflects off a loose end, the pulse inverts.

F.Suppose you pulse the generator one and wait for the pulse to make 1 round trip. At that moment, you pulse the generator a second time. For a fixed-loose string, the pulses constructively interfere completely.

G.Suppose you pulse the generator one and wait for the pulse to make 2 round trips. At that moment, you pulse the generator a second time. For a fixed-loose string, the pulses constructively interfere completely.

H.Suppose you pulse the generator one and wait for the pulse to make 3 round trips. At that moment, you pulse the generator a second time. For a fixed-loose string, the pulses constructively interfere completely.

I.Suppose you pulse the generator one and wait for the pulse to make 4 round trips. At that moment, you pulse the generator a second time. For a fixed-loose string, the pulses constructively interfere completely.

J.Suppose you pulse the generator one and wait for the pulse to make 1 round trip. At that moment, you pulse the generator a second time. For a fixed-fixed string, the pulses constructively interfere completely.

K.Suppose you pulse the generator one and wait for the pulse to make 2 round trips. At that moment, you pulse the generator a second time. For a fixed-fixed string, the pulses constructively interfere completely.

L.Suppose you pulse the generator one and wait for the pulse to make 3 round trips. At that moment, you pulse the generator a second time. For a fixed-fixed string, the pulses constructively interfere completely.

M.Suppose you pulse the generator one and wait for the pulse to make 4 round trips. At that moment, you pulse the generator a second time. For a fixed-fixed string, the pulses constructively interfere completely.

N.For a fixed-fixed string, pulsing the generator every 2 𝐿 / 𝑣 seconds (or, equivalently, with a frequency of 𝑣 / 2 𝐿 ) will result in all wave pulses constructively interfering. ( 𝐿 is the length of the string and 𝑣 is the string’s wavespeed.)

O.For a fixed-fixed string, pulsing the generator every 2 𝐿 / 𝑣 seconds (or, equivalently, with a frequency of 𝑣 / 2 𝐿 ) will result in all wave pulses destructively interfering.

P.For a fixed-loose string, pulsing the generator every 4 𝐿 / 𝑣 seconds (or, equivalently, with a frequency of 𝑣 / 4 𝐿 ) will result in all wave pulses constructively interfering.

Q.For a fixed-loose string, pulsing the generator every 4 𝐿 / 𝑣 seconds (or, equivalently, with a frequency of 𝑣 / 4 𝐿 ) will result in all wave pulses destructively interfering.

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Step-by-Step Analysis

The question presents a simulation study of wave pulses on a string with different boundary conditions and asks you to select all statements that are true based on the observed transit and interference behavior. Below is a option-by-option analysis to help you evaluate each claim. Option 1: "A pulse takes 2.4 seconds to make a round trip on this string (i.e., to travel from the wave driver, down the string, and back to the wave driver.)" - This statement asserts a specific round-trip time. To judge it, you would need the string length and the wave speed from the setup. If the simulated wave speed is about 0.06 m/s (as given in another option) and the round trip distance is twice the string length, you can compute time = 2L / v. For a round trip of 2.4 s, the implied 2L would be 0.144 m if v = 0.06 m/s, which may not align with the actual string length used in the simulation. Without the exact L and v values matching 2.4 s, this claim could be false. In short, unless the experiment’s L and v yield 2.4 s, this is likely incorrect. Option 2: "In one round trip on this string, the pulse traverses a distance of 7.6 m." - Round-trip distance equals twice the string length: 2L. If 2L = 7.6 m, then L = 3.8 m. This could be plausible if the simulated string length is 3.8 m. If the given wavespeed v and round-trip time align (since t = 2L/v), you could verify whether the numbers fit. If the simulation uses a different L, this statement is false. You should cross-check L from the setup; otherwise this remains uncertain. Option 3: "The wavespeed for the string is about 0.06 m/s." - This is a straightforward numerical claim about the medium. If you know the string’s tension and linear density from the simulation, you could compute v = sqrt(T/μ). A value of 0.06 m/s would imply specific μ given High tension and Amplitude settings. If the simulation’s parameters yield v ≈ 0.06 m/s, this is true; if not, it’s false. Check the derived v from the settings to decide. Option 4: "When a pulse reflects off a fixed end, the pulse inverts." - This is a standard boundary condition result: fixed (rigid) ends invert the pulse upon reflection, producing a reflected pulse of opposite phase. This statement i......Login to view full explanation

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