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Question at position 15 Predict the actual bond angles in N2F+ using the VSEPR theory. 109.5°less than 120° less than 109.5° 120° 90° 180°

Options
A.109.5°
B.less than 120°
C.less than 109.5°
D.120°
E.90°
F.180°
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Question restatement: Determine the actual bond angles in N2F+ as predicted by VSEPR theory, choosing from: 109.5°, less than 120°, less than 109.5°, 120°, 90°, 180°. Option analysis: - 109.5°: This angle is typical of a tetrahedral arrangement with four electron domains around a central atom. In N2F+, the central atom environment does not feature four regions of electron density; it has only two bonding partners (N and F) and no geometry requiring a te......Login to view full explanation

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