What is the reading on the voltmeter given the following values:Power supply: 5 VoltsR1: 5 OhmsR2: 8 OhmsR3: 6 Ohms

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To understand the voltmeter reading, first identify the circuit arrangement: R1 is in series with the parallel combination of R2 and R3, all fed by a 5 V source. The current through the circuit is determined by the total resistance, and the voltmeter reading corresponds to the voltage drop across R1 (the vertical resistor on the left in the branch connected to the supply).

Option a. 2.97 V: This value corresponds to the voltage drop across R1 when you compute the total resistance as R_total = R1 + (R2 || R3). The parallel part is (8 Ω * 6 Ω) / (8 Ω + 6 Ω) = 48 / 14 ≈ 3.4286 Ω. Therefore R_total ≈ 5 Ω + 3.4286 Ω ≈ 8.4286 Ω. The current I ≈ 5 V / 8.4286 Ω ≈ 0.593 A. The drop across R1 is V_R1 = I * R1 ≈ 0.593 A * 5 Ω ≈ 2.965 V, which rounds to 2.97 V. This aligns with the expected reading for the voltmeter across R1.

Option b. 0.593 V: This value looks like the current multiplied by a resistor of about 1 Ω (0.593 A × 1 Ω ≈ 0.593 V) or, less plausibly, a misinterpretation of current directly as voltage. It does not match the computed drop across any single resistor in this network, and using 0.593 V would imply an effective resistance of about 8.41 Ω being driven with 5 V, which is inconsistent with the given component values.

Option c. 2.03 V: This would correspond to a different partition of voltage than the one across R1. If you recompute with any misassignment of which resistor the voltmeter spans, you would not land exactly on 2.03 V given 5 V total and the specified resistor values. It suggests a misunderstanding of the parallel network or the measurement point.

Option d. 5.00 V: A reading of the full supply voltage would imply the voltmeter is measuring across nothing or across a zero-resistance path, which is not the case here. Since there is a definite load (R1 in series with the parallel of R2 and R3), the drop cannot equal the source voltage.

In summary, the only option that matches the calculated voltage drop across R1 in the described network is approximately 2.97 V, obtained from the current through the series path and the value of R1. The other options misinterpret the measurement location, the effect of the parallel branch, or the relationship between current, resistance, and voltage in this circuit.

MUF0122 Physics Unit 2 - Semester 2, 2025

What is the reading on the voltmeter given the following values:Power supply: 5 VoltsR1: 5 OhmsR2: 8 OhmsR3: 6 Ohms

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