Questions
UCIC 202503 PHYS101 Quiz 1
Single choice
A vector A has components Ax=3A_x = 3 and Ay=4A_y = 4. How can you determine its magnitude and direction?
Options
A.a. Use A=Ax2+Ay2A = A_x^2 + A_y^2 for magnitude and θ=sin−1(Ay/Ax)\theta = \sin^{-1} (A_y / A_x) for direction.
B.b. Use A=Ax×AyA = A_x \times A_y for magnitude and θ=cos−1(Ax/Ay)\theta = \cos^{-1} (A_x / A_y) for direction.
C.c. Use A=Ax+AyA = A_x + A_y for magnitude and θ=Ax/Ay\theta = A_x / A_y for direction.
D.d. Use A=Ax2+Ay2A = \sqrt{A_x^2 + A_y^2} for magnitude and θ=tan−1(Ay/Ax)\theta = \tan^{-1} (A_y / A_x) for direction.

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Step-by-Step Analysis
Let’s parse the problem: a vector A has components Ax = 3 and Ay = 4. We want to determine its magnitude and direction. Now, evaluate each option in turn.
Option a: Use A = sqrt(Ax^2 + Ay^2) for magnitude and θ = sin^−1(Ay/Ax) for direction.
- For the magnitude, A = sqrt(Ax^2 + Ay^2) is correct mathematically, but the direction using θ = sin^−1(Ay/Ax) is problematic. The ratio Ay/Ax gives the tangent of the angle in standard Cartesian coordinates (for a right triangle with adjacent side Ax and opposite side Ay), not the sine of the angle. Using sin^−1(Ay/Ax) can yield incorrect angles outside the principal range and eve......Login to view full explanationLog in for full answers
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