Question textWrite a C++ function that counts how many integers in a vector contain at least one occurrence of the digit given as a parameter. For example, given the following integer vector, and the function call: vector numbers = {1234,4355,6541,8976};int result = count_numbers_with_digit(numbers,4); The returned integer value must be 3 (The values in the vector with at least one 4 are: 1234, 4355, and 6541). The function's header is as follows: int count_numbers_with_digit(const vector & numbers, int digit) This function takes as parameters a vector containing positive integers greater than zero, and a single-digit positive integer representing the digit to find in each number stored in the vector. Notes: You can safely assume that the input is always valid. You do not need to write the main function. A 100% penalty will be applied to solutions that do not compile. A 100% penalty will be applied to solutions that hardcode the output. For example:[table] Test | Result vector numbers = {1234,4355,6541,8976}; int result = count_numbers_with_digit(numbers,4); if (result == 3) { cout

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Question textWrite a C++ function that counts how many integers in a vector contain at least one occurrence of the digit given as a parameter. For example, given the following integer vector, and the function call: vector numbers = {1234,4355,6541,8976};int result = count_numbers_with_digit(numbers,4); The returned integer value must be 3 (The values in the vector with at least one 4 are: 1234, 4355, and 6541). The function's header is as follows: int count_numbers_with_digit(const vector & numbers, int digit) This function takes as parameters a vector containing positive integers greater than zero, and a single-digit positive integer representing the digit to find in each number stored in the vector. Notes: You can safely assume that the input is always valid. You do not need to write the main function. A 100% penalty will be applied to solutions that do not compile. A 100% penalty will be applied to solutions that hardcode the output. For example:[table] Test | Result vector numbers = {1234,4355,6541,8976}; int result = count_numbers_with_digit(numbers,4); if (result == 3) { cout << "Correct implementation of the count_numbers_with_digit user-defined function" << endl; } else { cout << "Incorrect implementation of the count_numbers_with_digit user-defined function" << endl; cout << "Returned value: " << result << endl; cout << "Correct value: 3" << endl; } | Correct implementation of the count_numbers_with_digit user-defined function [/table] Answer:(penalty regime: 0 %)#ifndef FUNCTIONS_H #define FUNCTIONS_H #include using namespace std; // Write the definition and implementation of the count_numbers_with_digit user-defined function here int count_numbers_with_digit(const vector & numbers, int digit) { int count = 0; for (size_t i = 0; i < numbers.size(); ++i) { int num = numbers[i]; int d = digit; do { if (num % 10 == d) { ++count; break; } num /= 10; } while (num > 0); } return count; } #endif 1234567891011121314151617181920212223242526272829#ifndef FUNCTIONS_H#define FUNCTIONS_H#include using namespace std;// Write the definition and implementation of the count_numbers_with_digit user-defined function hereint count_numbers_with_digit(const vector & numbers, int digit){ int count = 0; int count = 0; for (size_t i = 0; i < numbers.size(); ++i) { int num = numbers[i]; int d = digit; do { if (num % 10 == d) { ++count; break; } num /= 10; } while (num > 0); } return count;}#endif ההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX Check Question 2

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Let me restate the task and the materials we have to work with to ground the analysis. The prompt asks for a C++ function that counts how many integers in a vector contain at least one occurrence of a specified single-digit parameter. The example given uses the vector {1234, 4355, 6541, 8976} and digit 4, producing 3 because 1234, 4355, and 6541 each contain the digit 4. The function header provided is: int count_numbers_with_digit(const vector & numbers, int digit). The notes specify inputs are positive integers (>0) and digit is a single-digit positive integer; main is not required, and the code must compile. In the material, there is a candidate implementation embedded within a larger HTML-like page; for this analysis I will treat the relevant implementation as the candidate solution to scrutinize. Option/Code under evaluation: int count_numbers_with_digit(const vector & numbers, int digit) { int count = 0; for (size_t i = 0; i < numbers.size(); ++i) { int num = numbers[i]; int d = digit; do { if (num % 10 == d) { ++count; break; } num /= 10; } while (num > 0); } return count; } Now, let’s analyze the approach and each aspect of the solution step by step. First, the overall strategy. The function iterates over every integer in the input vector and, for each number, scans its decimal digits from least significant to most significant, using num % 10 to extract digits and num /= 10 to move to the next digit. If any extracted digit equals the target digit, it increments the count and breaks out of the inner loop to proceed to the next number. This approach correctly detects whether a given number contains the target digit at least once, and only increments the count once per number, which matches the problem statement. Now, option-by-option reasoning (adjusted because only a single candidate solution is present): - Correctness aspects of the digit-check loop: The inner logic uses a do-while loop to ensure that even a number consisting of a single digit is checked (for example, 4). The condition if (num % 10 == d) detects whether the current least-significant digit matches the target digit. If a match is found, ++count is performed and break exits the inner loop early for that number, which is efficient and correct because each number should contribute at most 1 to the total count. After each unsuccessful digit check, num is reduced by removing the least-significant digit via num /= 10, moving to the next digit. The loop continues while (num > 0). This ensures all digits are checked. Therefore, for a valid positive integer input, this logic correctly identifies whether the number contains the specified digit. - Handling of the outer loop over numbers: The outer loop iterates for i from 0 to numbers.size() - 1, accessing numbers[i] each time. This visits every element of the vector exactly once, which is exactly what the problem requires: assess each number independently and count how many satisfy the condition. - Time and space complexity considerations: In the worst case, each number with k digits requires examining all k digits until a match is found or all digits are exhausted. If no number contains the digit, the inner loop runs through all digits of each number. The overall time complexity is O(N * D), where N is numbers.size() and D is the average number of digits per number (bounded by a constant for typical int ranges). The space complexity is O(1) beyond the input vector, since only a few integer variables (count, i, num, d) are stored. - Edge cases and constraints validation: The function assumes input is valid as per the prompt, so it does not validate that digit is a single decimal digit. If digit were outside 0-9, the behavior would still compile but would not align with the stated contract; in a strictly defensive implementation, one might add an assertion or a runtime check. Since the prompt guarantees a single-digit positive integer, this is acceptable here. The code uses int for count; this is sufficient for typical use cases where the vector size is well within int limits. If extremely large vectors were possible, one might consider using size_t for the count, but for the problem’s scope, int is standard and compatible with the header signature. - Style and compatibility notes: The function signature matches the given header exactly, taking a const vector& and an int digit. It relies only on standard operations and uses no non-standard libraries, so it should compile cleanly provided the surrounding headers declare vector (e.g., #include ) in the actual compilation unit. The example snippet in the prompt mentions a minimal header guard and includes , but the essential dependencies for vector are and possibly for size_t; the provided snippet omits in the shown region, which could be a compilation issue if not present in the real header. In many environments, adding #include would be necessary for portability. - Potential variations or common mistakes to compare against: A common pitfall is counting multiple occurrences of the digit within a single number; this solution avoids that by breaking after the first match for a number, which is correct per the problem statement. Another pitfall is not handling the digits correctly when the number is large or when the digit is 0; since the problem states positive integers greater than zero and a single-digit positive digit, the approach here handles digits 0–9 uniformly in principle, though 0 would require ensuring that 0 is treated as a valid digit if included in numbers; in the given constraints, the digit is positive, so 0 is not a concern. - Summary observation of alignment with the task: The implementation adheres to the required interface, processes each number exactly once, checks all digits efficiently, increments the count only once per number that contains the digit, and returns the correct total count. It matches the intended semantic: count how many integers in the vector contain at least one occurrence of the specified digit, with a time-efficient and straightforward digit-scanning approach. In conclusion, the code provided implements a clear and correct solution under the stated constraints, with behavior that aligns with the example and the function contract. The only caveat to watch in a broader context is ensuring the necessary headers (such as #include ) are included in the compilation unit for full portability.

COSC 1437 - 15099 - Introduction to Programming

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