Consider the following code:
x := 5
y := 6
y := x

What is the final value of y after the code is executed?

Question

Consider the following code:
x := 5  
y := 6  
y := x

What is the final value of y after the code is executed?

BlackTom AI · Accepted Answer

First, let's restate what the code does step by step to ground our analysis.
- Initially, x is assigned the value 5.
- Then, y is assigned the value 6.
- Finally, y is reassigned to the value of x, which is currently 5.
---
Option A: '5' — This matches the final assignment of y to x's value, so y ends up as 5. The reasoning here is that the last line overwrites the previous value of y with x's value at that moment.
Option B: '6' — This would be correct if there were no subsequent assignment to y after y was initially set to 6. Since there is y := x afterward, y takes on 5, not 6.
Option C: '11' — This would imply a sum or a mistaken combination of 5 and 6, which does not occur in the given code. There is no arithmetic operation that produces 11 here.
Option D: 'None of the above' — Since one of the listed options (A) accurately reflects the final value of y, this choice is incorrect.
---
To summarize the key idea: the final value of y is determined by the last assignment to y, which assigns x’s current value to y. Because x is 5 and that value is copied into y at the end, the final result is 5, not 6 or 11, and not 'none of the above'.

Consider the following code: x := 5 y := 6 y := x What is the final value of y after the code is executed?

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