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FA25_QTM_100_3 Final Exam- Requires Respondus LockDown Browser

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Each year the US Environmental Protection Agency (EPA) releases fuel economy data on cars manufactured in that year. Below are summary statistics on fuel efficiency (in miles/gallon) from random samples of small cars with manual and automatic transmissions. Which of the following statements is true if we were to decide whether or not these data provide strong evidence of a difference between the average fuel efficiency of cars with manual and automatic transmissions in terms of their average city mileage? Assume that conditions for inference are satisfied. Automatic Manual Mean 32.4 28.8 Standard Deviation 2.12 5.75 n 27 26

Options
A.The degrees of freedom for this hypothesis test is 25.
B.When calculating the standard error, we first pool the standard deviations from both samples because we assume no differences in variabilities between the two samples.
C.A paired t-test is the appropriate test to use.
D.We can assume equal variances because the sample sizes are similar for both samples.
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Let's carefully examine each statement about the two-sample inference scenario described. Option 1: 'The degrees of freedom for this hypothesis test is 25.' - In a two-sample t-test, the degrees of freedom depend on which version of the test we use. If we pool the variances (assuming equal variances), the standard two-sample t-test uses df = n1 + n2 − 2, which here would be 27 + 26 − 2 = 51. If we do not assume equal variances (the Welch t-test), the degrees of freedom are computed by a more complicated formula that typically yields a value between the smaller of (n1 − 1) and (n2 − 1) and something larger, often not an integer, and certainly not a fixed 25 in this setup. Specifically, min(n1 − 1, n2 − 1) = min(26, 25) = 25 provides only a roug......Login to view full explanation

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A two-sided independent samples t-test with n1=33 and n2=38 yielded a test statistic of 2.03. Assuming unequal variances, which of the following is the correct p-value for this hypothesis test? Be sure to find the p-value using the t-distribution probability table.

A researcher was interested in comparing the response times of two different cab companies. Companies A and B were each called at 50 randomly selected times.  The calls to company A were made independently of the calls to company B. The response times for each call were recorded. The summary statistics were as follows: Use a 0.01 significance level to test the claim that  the mean response time for company A is the same as  the mean response time for company B.  Based on the sample standard deviations, it seems safe to assume that the variances are the same. The data is listed below.   Complete the following analysis. 1. This is a [ Select ] right two left -tailed test. 2. The test statistic is equal to t=2.248 . 3. The P-value is equal to [ Select ] 0.08211405 0.02681 0.09728 . 4. [ Select ] Fail to reject Reject the null hypothesis. 5. At the 1% significance level, it [ Select ] appears that does not appear that the mean response time for company A is different from the mean response time for Company B.   A - 6.424 , 7.768 , 6.088 , 10.12 , 7.936 , 6.088 , 8.272 , 8.608 , 8.44 , 6.928 , 9.952 , 8.104 , 6.424 , 3.736 , 9.28 , 7.432 , 7.432 , 8.944 , 8.776 , 8.44 , 8.944 , 8.776 , 7.6 , 4.072 , 8.44 , 7.264 , 7.096 , 4.912 , 6.592 , 8.104 , 9.784 , 7.264 , 8.104 , 7.264 , 5.08 , 6.76 , 6.76 , 7.264 , 9.28 , 8.776 , 7.096 , 6.928 , 8.608 , 8.44 , 6.256 , 6.256 , 8.104 , 8.776 , 7.264 , 8.944   B - 7.376 , 5.625 , 7.2009 , 4.7495 , 9.127 , 10.1776 , 5.9752 , 4.9246 , 7.7262 , 6.5005 , 10.878 , 6.6756 , 7.9013 , 6.6756 , 5.4499 , 7.0258 , 3.5238 , 9.3021 , 7.0258 , 10.5278 , 7.5511 , 5.4499 , 7.7262 , 5.0997 , 4.3993 , 7.2009 , 5.9752 , 6.6756 , 6.8507 , 5.625 , 5.625 , 6.5005 , 8.7768 , 4.0491 , 7.7262 , 7.2009 , 8.6017 , 6.1503 , 7.376 , 7.2009 , 5.8001 , 8.7768 , 8.7768 , 7.9013 , 9.4772 , 7.7262 , 4.3993 , 5.625 , 4.5744 , 5.8001     c08.p084.q012    

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