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BTRY3010/BTRY5010/STSCI2200/STSCI5200 Lecture #26 Pages ( 126 - 129, 134 )

Multiple choice

A researcher was interested in comparing the amount of time (in hours) spent watching television by women (pop 1)  and by men ( pop 2 ). Independent simple random samples of 14 women and 17 men were selected, and each person was asked how many hours he or she had watched television during the previous week. The summary statistics are as follows. Pop 1 Pop 2 Samp. Mean 12.5 13.5 Samp. SD 3.4 6.4 Samp Size 14 17   Use a 0.05 significance level to test the claim that the mean amount of time spent watching television by women is LARGER than the mean amount of time spent watching television by men.   WhAT WOULD BE THE HYPOTHESES FOR THIS TEST? c08.p084.q002  

Options
A.𝐻 0 : 𝑝 1 = 𝑝 2
B.𝐻 0 : 𝜇 1 = 𝜇 2
C.𝐻 1 : 𝜇 1 > 𝜇 2
D.𝐻 1 : 𝑝 1 < 𝑝 2
E.𝐻 1 : 𝜇 1 < 𝜇 2
F.𝐻 1 : 𝑝 1 ≠ 𝑝 2
G.𝐻 1 : 𝜇 1 ≠ 𝜇 2
H.𝐻 1 : 𝑝 1 > 𝑝 2
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Step-by-Step Analysis
The task is to identify the proper null and alternative hypotheses for comparing mean hours of TV watched between women (population 1) and men (population 2), with the claim that women watch more on average. Option 1: H0: p1 = p2. This uses proportions (p1 and p2) rather than means μ1 and μ2. Since the question concerns mean hours watched, this is not appropriate here. It mis-specifies the parameter of ......Login to view full explanation

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A researcher was interested in comparing the response times of two different cab companies. Companies A and B were each called at 50 randomly selected times.  The calls to company A were made independently of the calls to company B. The response times for each call were recorded. The summary statistics were as follows: Use a 0.01 significance level to test the claim that  the mean response time for company A is the same as  the mean response time for company B.  Based on the sample standard deviations, it seems safe to assume that the variances are the same. The data is listed below.   Complete the following analysis. 1. This is a [ Select ] right two left -tailed test. 2. The test statistic is equal to t=2.248 . 3. The P-value is equal to [ Select ] 0.08211405 0.02681 0.09728 . 4. [ Select ] Fail to reject Reject the null hypothesis. 5. At the 1% significance level, it [ Select ] appears that does not appear that the mean response time for company A is different from the mean response time for Company B.   A - 6.424 , 7.768 , 6.088 , 10.12 , 7.936 , 6.088 , 8.272 , 8.608 , 8.44 , 6.928 , 9.952 , 8.104 , 6.424 , 3.736 , 9.28 , 7.432 , 7.432 , 8.944 , 8.776 , 8.44 , 8.944 , 8.776 , 7.6 , 4.072 , 8.44 , 7.264 , 7.096 , 4.912 , 6.592 , 8.104 , 9.784 , 7.264 , 8.104 , 7.264 , 5.08 , 6.76 , 6.76 , 7.264 , 9.28 , 8.776 , 7.096 , 6.928 , 8.608 , 8.44 , 6.256 , 6.256 , 8.104 , 8.776 , 7.264 , 8.944   B - 7.376 , 5.625 , 7.2009 , 4.7495 , 9.127 , 10.1776 , 5.9752 , 4.9246 , 7.7262 , 6.5005 , 10.878 , 6.6756 , 7.9013 , 6.6756 , 5.4499 , 7.0258 , 3.5238 , 9.3021 , 7.0258 , 10.5278 , 7.5511 , 5.4499 , 7.7262 , 5.0997 , 4.3993 , 7.2009 , 5.9752 , 6.6756 , 6.8507 , 5.625 , 5.625 , 6.5005 , 8.7768 , 4.0491 , 7.7262 , 7.2009 , 8.6017 , 6.1503 , 7.376 , 7.2009 , 5.8001 , 8.7768 , 8.7768 , 7.9013 , 9.4772 , 7.7262 , 4.3993 , 5.625 , 4.5744 , 5.8001     c08.p084.q012    

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