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Part 1Solve the right triangle. Part 1 49 degrees 26 prime49° 26′ABCab961 m Part 1Bequals=[input]4141 degrees° [input]negative 26−26 prime′ (Round to the nearest integer as needed.)aequals=[input]961961 m (Round to the nearest integer as needed.)bequals=[input]823823 m (Round to the nearest integer as needed.)

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Let's begin by restating what the problem is asking and what information is given. - The task is to solve a right triangle, with an angle of 49°26' (49 degrees and 26 minutes) provided. There are blanks to fill for the other angle and one or more side lengths, and the provided answer list includes 41°34′, 961, and 723. - However, the exact labeling of sides (a, b, c) relative to the angles is not clearly shown in the text snippet, which makes it ambiguous which blank corresponds to which quantity (hypotenuse, a leg, or an adjacent/opposite side). I will proceed with the standard conventions and point out any ambiguities as they arise. Step 1: Determine the other acute angle in the right triangle. - In any right triangle, the sum of the two acute angles is 90 degrees (since the total around a point is 180 degrees, and one angle is 90° for a right triangle). - If one acute angle is 49°26', then the other acute angle B must be 90° − 49°26'. - Convert 49°26' to decimal for a quick check: 26 minutes is 26/60 = 0.4333..., so 49°26' ≈ 49.4333°. Then 90° − 49.4333° ≈ 40.5667°, which is 4......Login to view full explanation

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