The non-coding strand of a region of double-stranded DNA has the sequence 5′-TCAGTGAGTATACATGGC-3′.Assuming standard initiation of translation, what is the corresponding polypeptide that would be encoded by the coding strand?Type in your answer below using the single amino acid code.[Do not type any additional characters. For example, if your answer is “PEPTIDE” followed by a stop codon, simply type in: PEPTIDE]

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BlackTom AI · Accepted Answer

The question provides the non-coding (template) strand sequence in the 5' to 3' direction: 5'-TCAGTGAGTATACATGGC-3'. To determine the encoded polypeptide, we can follow these steps:

- First, identify the coding strand by computing the reverse complement of the non-coding strand. Complementing T with A, C with G, A with T, and G with C gives the intermediate complement strand in the 3' to 5' direction. Reversing this result yields the coding strand in the 5' to 3' orientation.
- The reverse complement (coding strand) in 5' to 3' is: GCCATGTATACTCACTGA.
- Next, convert this coding strand into the mRNA sequence by replacing each T with U (since transcription produces an RNA strand with uracil). The resulting mRNA sequence is: GCCAUGUAUACUCA CUGA -> specifically GCCAUGUAUACUCA CUGA, which translates to codons as follows: GCC | AUG | UAU | ACU | CAC | UGA.
- Now translate codons into amino acids using the standard genetic code:
  - GCC encodes Alanine (A)
  - AUG encodes Methionine (M) and also serves as the start codon
  - UAU encodes Tyrosine (Y)
  - ACU encodes Threonine (T)
  - CAC encodes Histidine (H)
  - UGA is a stop codon, terminating translation
- Therefore, the polypeptide sequence produced before termination is: Alanine – Methionine – Tyrosine – Threonine – Histidine, abbreviated in one-letter codes as AMYTH.

Consider the provided answer of MY. This would correspond to a peptide comprising only Methionine and Tyrosine, which would ignore the remaining codons in this reading frame (Ala, Thr, and His) and would imply an incomplete translation with an early stop that is not supported by the given sequence. The presence of a valid start codon (AUG) and the subsequent codons in the same frame clearly yields AMYTH before encountering the stop codon UGA.

In summary, the encoded polypeptide, following standard initiation of translation and reading frame from the identified start codon, is AMYTH; the answer MY does not account for the full coding sequence and therefore is incorrect.

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