Consider the following code segment:

x = 12
print("%d%%" % x)

The output generated by this code segment is:

Question

Consider the following code segment:

x = 12
print("%d%%" % x)

The output generated by this code segment is:

BlackTom AI · Accepted Answer

The code uses Python string formatting with the old %-style syntax. The format string is "%d%%" and the value to substitute is x = 12. Here, %d is a placeholder for a decimal integer, and %% is the escape sequence that prints a literal percent sign.

Option 1: "12%%". This would display a literal percent sign twice if the format string contained two percent escapes, but the actual output uses a single literal percent sign after the number, so this is not correct.

Option 2: "12%". This matches the expected behavior: the integer 12 is substituted for %d, and the subsequent %% in the format string becomes a single % character in the output, yielding 12%.

Option 3: "12". If the format string did not include any percent escape for a symbol after the number, you would only get the number itself; however, the format string explicitly includes the escaped percent sign, so this option omits the required % character and is incorrect.

Option 4: "%12". This resembles a width specifier in some formatting contexts, but in %-style formatting, a standalone "%12" would be invalid or would attempt to interpret 12 as part of the specifier. The given code does not produce this form, so this option is incorrect.

In summary, the correct behavior is that the string "12%" is produced, due to %d substituting the integer 12 and %% translating to a single % character. The other choices misinterpret how the format specifiers are applied or ignore the literal percent escape.

Fal25_CS003C_74229 Ch. 2 Pre-Quiz (Remotely Proctored)

Consider the following code segment: x = 12 print("%d%%" % x) The output generated by this code segment is:

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