We have 35 kg of carbon dioxide. How much methane is it possible to get from it?Reaction equation of Sabatier reaction CO2 + 4 H2 ↔ CH4 + 2 H2OGive your answer in kg (kilograms) and round it to one decimal place.

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The problem asks for the maximum amount of CH4 that can be produced from 35 kg of CO2 using the Sabatier reaction: CO2 + 4 H2 -> CH4 + 2 H2O.
First, determine the reactant moles: the molar mass of CO2 is about 44.01 g/mol. 35,000 g / 44.01 g/mol ≈ 795.5 mol of CO2 available.
Next, apply the reaction stoichiometry: 1 mole of CO2 yields 1 mole of CH4. Therefore, the moles of CH4 possible are also ≈ 795.5 mol.
Now convert to mass: the molar mass of CH4 is about 16.04 g/mol. 795.5 mol × 16.04 g/mol ≈ 12,756 g of CH4.
Convert grams to kilograms: 12,756 g ≈ 12.756 kg.
Finally, round to one decimal place as requested: 12.8 kg.
Notes on rounding and precision: using typical molar masses (CO2 ≈ 44.01 g/mol, CH4 ≈ 16.04 g/mol) yields the result close to 12.76–12.76 kg, which rounds to 12.8 kg. The computation hinges entirely on the 1:1 mole ratio between CO2 and CH4 in the Sabatier reaction, so no other limiting reagents need to be considered for this conversion once CO2 moles are known.

Climate Action - PtX Mass calculation

We have 35 kg of carbon dioxide. How much methane is it possible to get from it?Reaction equation of Sabatier reaction CO2 + 4 H2 ↔ CH4 + 2 H2OGive your answer in kg (kilograms) and round it to one decimal place.

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