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A uniform beam of mass 5 kg is hinged to a wall and supported at its outer end by a wire as shown. The outer end supports a 10 kg load, also shown: The tension in the wire is:

Options
A.A. 245 N
B.B. 122.5 N
C.C. impossible to calculate without knowing the length of the beam.
D.D. 204 N
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Step-by-Step Analysis
To tackle this problem, focus on rotational equilibrium about the hinged wall. Option A: 245 N. This would arise if you computed the torque balance as T_y × L = g(5 × L/2 + 10 × L) but used sin(36.9°) = 0.5 instead of the actual value. Since sin(36.9°) is about 0.6, using 0.5 leads to an overestimate of T by a factor of 0.5/0.6, yielding roughly 245 N. This shows a misapplic......Login to view full explanation

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