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SPHY001 Practice Quiz - Unit 17 | LA057

Single choice

A string, 6.0 meters in length, is fixed at both ends and tightened until the wave speed is 100 m/s. What is the frequency of the standing wave shown in the figure?  

Options
A.200 Hz
B.50 Hz
C.100 Hz
D.25 Hz
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Step-by-Step Analysis
Start by identifying the general relationship for standing waves on a string fixed at both ends. The allowed wavelengths are λ_n = 2L/n, where L is the string length and n is the harmonic number (n = 1, 2, 3, ...). The corresponding frequency is f_n = v/λ_n = n v /(2L). Given: L = 6.0 m and v = 100 m/s, so f_n = n × 100 / (2 × 6) = n × 100 / 12 ≈ 8.33 n H......Login to view full explanation

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