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Physics 1 Hon - Bowles - p06/p07 CFE Practice - Light

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A candle is located 30 cm in front of a concave spherical mirror having principal focus f = 10 cm, as shown in the diagram below. What is the image distance? [ Select ] 15 cm 7.5 cm 0.067 cm -30 cm What is the magnification? [ Select ] -2.0 x -0.5 x -7.5 x -1.0 x What are the image characteristics? [ Select ] real, reduced, and inverted virtual, reduced, and upright real, enlarged, and inverted virtual, enlarged, and inverted   

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To begin, let's outline what the problem is asking: a candle is placed 30 cm in front of a concave mirror with focal length f = 10 cm. We must determine the image distance v, the magnification m, and the image characteristics. Option group 1 (image distance): 15 cm, 7.5 cm, 0.067 cm, -30 cm First, apply the mirror equation: 1/f = 1/v + 1/u. Using the sign convention where distances measured in front of the mirror are positive, the object distance u = +30 cm and f = +10 cm. Substituting gives 1/10 = 1/v + 1/30. Solve: 1/v = 1/10 − 1/30 = ......Login to view full explanation

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A candle is located 30 cm in front of a concave spherical mirror having principal focus f = 10 cm, as shown in the diagram below. What is the image distance? [ Select ] 15 cm 7.5 cm 0.067 cm -30 cm What is the magnification? [ Select ] -2.0 x -0.5 x -7.5 x -1.0 x What are the image characteristics? [ Select ] real, reduced, and inverted virtual, reduced, and upright real, enlarged, and inverted virtual, enlarged, and inverted   

A candle is located 30 cm in front of a concave spherical mirror having principal focus f = 10 cm, as shown in the diagram below. What is the image distance? [ Select ] 15 cm 0.067 cm 7.5 cm -30 cm What is the magnification? [ Select ] -0.5 x -1.0 x -2.0 x -7.5 x What are the image characteristics? [ Select ] real, reduced, and inverted real, enlarged, and inverted virtual, enlarged, and inverted virtual, reduced, and upright   

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