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Physics 1 Hon - Bowles - p06/p07 CFE Practice - Light

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A candle is located 30 cm in front of a concave spherical mirror having principal focus f = 10 cm, as shown in the diagram below. What is the image distance? [ Select ] 15 cm 0.067 cm 7.5 cm -30 cm What is the magnification? [ Select ] -0.5 x -1.0 x -2.0 x -7.5 x What are the image characteristics? [ Select ] real, reduced, and inverted real, enlarged, and inverted virtual, enlarged, and inverted virtual, reduced, and upright   

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To analyze this problem, I will evaluate each choice for image distance, then each choice for magnification, and finally the image characteristics, using the mirror equation and magnification concept. Image distance options: - 15 cm: If we adopt the common sign convention where distances measured from the mirror along the incident light are positive for real measurements in front of the mirror, using the concave mirror with f = +10 cm and object distance u = +30 cm, the mirror equation 1/f = 1/v + 1/u becomes 1/10 = 1/v + 1/30. Solving gives 1/v = 1/10 − 1/30 = 3/30 − 1/30 = 2/30 = 1/15, so v = 15 cm. This yields a real image located 15 cm in front of the mirror. - 0.067 cm (about 0.067 cm): This value is inconsistent with the given focal length and typical image distances for a 30 c......Login to view full explanation

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