Questions
Multiple choice
Junior chemist must prepare 500.0 mL of a stock solution of 1.00 M sodium chloride using solid sodium chloride, deionized water, and laboratory glassware. Accurate preparation of a solution of specific molarity requires several steps. Read each procedural step described below and select all that are correct.
Options
A.Weigh out the calculated amount of solid to the nearest thousandths of a gram.
B.Fill the volumetric flask with exactly 500.0 mL of deionized water.
C.Add all the solid to the volumetric flask, add water to the line, and then mix to dissolve.
D.Use a volumetric flask that contains 500.0 mL when filled to the line.
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Step-by-Step Analysis
First, consider the goal: to prepare 500.0 mL of a 1.00 M NaCl solution from solid NaCl.
Option 1: Weigh out the calculated amount of solid to the nearest thousandths of a gram. For 0.500 L at 1.00 M, you need 0.500 mol of NaCl. With a molar mass of about 58.44 g/mol, the required mass is 0.500 × 58.44 ≈ 29.220 g. Weighing t......Login to view full explanationLog in for full answers
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Similar Questions
You are being interviewed for a high paying laboratory position. Your final interview question is this. "Explain in detail how you would go about preparing 1.00L of a 1.00 M solution of sodium chloride."
Before coming to lab a plan is needed for the creation of 5 standard aqueous solutions of (NH4)3Fe(ox)3.3H2O with concentrations between 1.0 x 10-3 M and 7.5 x 10-3 M. The first step is to create 25 mL of 0.012 M stock solution with (NH4)3Fe(ox)3.3H2O(s) and deionized water. What is the formula weight of (NH4)3Fe(ox)3.3H2O? [ Select ] 392,03 406.02 428.06 391.99 What mass (in grams) of (NH4)3Fe(ox)3.3H2O is required to make such a solution? [ Select ] 0.040 0.121 1.34 0.128 What piece of glassware holds the 25 mL? [ Select ] graduated cylinder Erlenmeyer flask beaker volumetric flask If the digital scale in lab reports values to the thousandths place, how many significant figures can the actual stock solution concentration be reported with? [ Select ] 3 2 4 1 5
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