金星比地球更靠近太阳，金星的太阳常数是……

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题干重述:
- 问：金星比地球更靠近太阳，因此金星的太阳常数是高于地球、低于地球，还是相等？
- 给定选项：只有一个选项“高于地球”。
分析各选项:
- 选项“高于地球”：这是正确的方向性判断。因为太阳常数与距离的平方成反比，即 S ∝ 1/r^2。金星与太阳的平均距离约为 0.723 AU，相对于地球的 1 AU，金星处的光强按 1/0.723^2≈1.92 的倍率增加，理论上约为地球的 1.9 倍。因此金星的太阳常数确实高于地球的太阳常数。
- 关于其他潜在问法（若存在其他选项）：需要比较太阳常数的绝对数值和相对关系。太阳常数只取决于距离，与行星的地理特性（如反照率、云层等）无关，因为太阳常数是单位面积上直接接收到的太阳辐射功率，不受目标物体反射/吸收特性的影响。
- 选项为何不涉及其他对比（如“低于地球”或“相等”之类的说法）：基于距离平方律，距离更近的天体应接收更强的太阳辐射，除非涉及极端特殊情形（如大气层显著阻挡），但在太阳常数的定义下，仍以距离决定强度级别，因此“高于地球”是符合物理规律的结论。
- 额外说明：若将来提供完整的选项集，可以逐条对比，应用 S_Venus = S_Earth × (1 AU / 0.723 AU)^2 的计算，直接得到相对因子并判断大小关系。当前只有这一选项，结论性判断会依赖于它是否正确表达了“更高”的关系。

CLMTGR5001_002_2025_3 - 气候变化和变化的动力学测验 2b 第 2 周第 2 讲

金星比地球更靠近太阳，金星的太阳常数是……

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CLMTGR5001_002_2025_3 - 气候变化和变化的动力学测验 2b 第 2 周第 2 讲