Questions
Physics 1 Hon - Bowles - p06/p07 P10.2 - Lesson 4 Exit Ticket
Short answer
A ray of light in air is approaching the boundary with water (n = 1.333) at an angle of 37.1 degrees. Determine the angle of refraction of the light ray.
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Step-by-Step Analysis
We are given light transitioning from air into water, so apply Snell's law: n1 sin(theta1) = n2 sin(theta2).
Here n1 is the refractive index of air, approximately 1.000, and n2......Login to view full explanationLog in for full answers
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Light exits a diamond (n = 2.42) into air. The angle of incidence is 15.0°. What is the angle of refraction?
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A light ray passes from water (refractive index ( n1 = 1.33 )) into diamond (refractive index ( n2 = 2.42 )). If the angle of incidence in water is ( 300 ), what is the angle of refraction in diamond?
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