Still overwhelmed by exam stress? You've come to the right place!
We know exam season has you totally swamped. To support your studies, access Gold Membership for FREE until December 31, 2025! Normally £29.99/month. Just Log In to activate – no strings attached.
Let us help you ace your exams efficiently!
Questions
PHYSICS 1201 SU2025 (10585) MT2 Exam- Requires Respondus LockDown Browser
Single choice
A beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 40° with the normal, and the refracted beam makes an angle of 26° with the normal. What is the speed of light in the transparent material? (c = 3.0 × 108 m/s, The refractive index of air , nair = 1)
Options
A.1.0 × 108 m/s
B.3.0 × 108 m/s
C.2.0 × 108 m/s
D.2.3 × 108 m/s
E.0.50 × 108 m/s
View Explanation
Standard Answer
Please login to view
Approach Analysis
To analyze the problem, recall that light slows down when entering a medium and slows according to the refractive index via Snell's law: n1 sin(theta1) = n2 sin(theta2).
Option by option evaluation:
- Option: 1.0 × 10^8 m/s
This would imply a refractive index n2 = c/v ≈ (3.0×10^8)/(1.0×10^8) = 3.0, which is much larger than the typical r......Login to view full explanationLog in for full answers
We've collected over 50,000 authentic exam questions and detailed explanations from around the globe. Log in now and get instant access to the answers!
Similar Questions
Question text1. Assume that we have a planet with a spherically uniform P wave speed distribution. The P wave speed at any depth is given by: [math: v(r)=8+16(1−(r/R)2)] Where [math: r] is the distance from the core of the planet, and [math: R=8200km] is the radius of the planet. a) A P wave is generated at the surface at an angle [math: θ0=32∘] from the surface normal. Calculate to three significant figures, in degrees, the angle of refraction at a depth of 110 km. Hint: Snell's law in a spherically symmetric Earth is given by [math: r1sin(θ1)v1=r2sin(θ2)v2] Refraction angle = Answer 1 Question 8[input] degrees [4] b) Calculate the maximum depth at which the ray travels, in km to three significant figures. Hint: At the maximum depth you will have a refraction angle of [math: 90∘].Maximum depth = Answer 2 Question 8[input] km [6]
Question at position 1 Given the figure below where light travels from one medium to another, and with Snell's Law in mind as well as the difference between the angles apparent; what is the relationship between the refractive indices n_1 and n_2? n_1 > n_2n_1 < n_2n_1 = n_2Not enough information
A light ray passes from water (refractive index ( n1 = 1.33 )) into diamond (refractive index ( n2 = 2.42 )). If the angle of incidence in water is ( 300 ), what is the angle of refraction in diamond?
Which of the following statements best describes Snell's Law and its application in determining the path of light as it passes from one medium to another?
More Practical Tools for International Students
Making Your Study Simpler
To make preparation and study season easier for more international students, we've decided to open up Gold Membership for a limited-time free trial until December 31, 2025!